All categories

3 years ago

Which set of ordered pairs represents a function?

Physics

2 answers:

Korolek [52]3 years ago

6 0

Answer:

{(-6, -9), (-6,4),(-1,9), (5, -1)}

Explanation:

because the x value is not repeated twice as it is in {(-8, -2), (7, -2),(-9,2), (0,0) {(5,8), (9,7),(-3,-8),(5,-5)} {(7,-8), (7, - 7), (8,4),(1, -3)}

olchik [2.2K]3 years ago

3 0

Answer:

The second one is a function. {(-8, -2), (7, -2),(-9,2), (0,0)

Explanation:

Its because the y-value is repeated twice.

Hope it helps.

You might be interested in

Which list of elements contains only metals?

fredd [130]

C. those are all metals.

6 0

4 years ago

Read 2 more answers

Which of Newton’s three laws applies?

siniylev [52]

Answer:

Newton's 1st law of motion

Explanation:

7 0

3 years ago

Read 2 more answers

Do we have free will or is everything predestined?

S_A_V [24]

Predestination, in theology, is the doctrine that all events have been willed by God, usually with reference to the eventual fate of the individual soul. Explanations of predestination often seek to address the "paradox of free will", whereby God's omniscience seems incompatible with human free will.

4 0

3 years ago

Read 2 more answers

I’ll give points plz and brainliest I know the result I just need the process.

shusha [124]

Shiddd ion even know but can you like my comment?

7 0

3 years ago

You illuminate a slit with a width of 71.7 μm with a light of wavelength 737 nm and observe the resulting diffraction pattern on

miskamm [114]

To solve this problem we will apply the concepts related to the double slit-experiment. Under this concept we understand the relationship between the minimum angle, depending on the order of the fringes, the wavelength and the distance between slits. Therefore we have the following relation,

$sin(\theta_{min}) = \frac{m\lambda}{D}$

Here,

m = Order of the fringes

D = Distance between slits

$\lambda$ = Wavelength

Replacing with our values we have,

$sin(\theta_{min}) = \frac{(1)(737*10^{-9})}{71.7*10^{-6}m}$

$sin(\theta_{min}) = 0.01028$

Through the relationship between distances then we have that the basic amplification distance is given by the relationship between the distance of the slit L and the angle, then

$Y=Lsin\theta$

$Y =2.27*0.01028$

$Y =0.0233m$

Thus the width of the central maximum is

$W=2Y=2*0.0233$

$W = 0.0466m$

Therefore the widht is 0.466m

6 0

4 years ago