Hello!
A graph that shows how position is depending on time is known as a Position Time Graph.
This is a graph used in Physics to help us understand how motion (positive/negative velocity) changes over a period of time. Motion can be seen in two ways on this graph: constant velocity and changing velocity, otherwise known as acceleration.
Hopes this help you answer your question!
A) the periodic time is given by the equation;
T= 2π√(L/g)
For the frequency will be obtained by 1/T (Hz)
T = 2 × 3.14 √ (0.66/9.81)
= 6.28 × √0.0673
= 1.6289 Seconds
Frequency = 1/T = f = 1/1.6289
thus; frequency = 0.614 Hz
b) The vertical distance, the height is given by
h= 0.66 cos 12
h = 0.65 m
Vertical fall at the lowest point = 0.66 - 0.65 = 0.01 m
Applying conservation of energy
energy lost (MgΔh) = KE gained (1/2mv²)
mgh = 1/2mv²
v² = 2gΔh = 2×9.81 × 0.01
= 0.1962
v = 0.443 m/s
c) total energy = KE + GPE = KE when GPE is equal to zero (at the lowest point possible)
Thus total energy is equal to;
E = 1/2mv²
= 1/2 × 0.310 × 0.443²
= 0.0304 J
Answer:
Final velocity of the car will be -9.28 m/sec
Explanation:
We have given that the car starts from the rest so initial velocity of the car u = 0 m /sec
Acceleration of the car
in negative direction so acceleration will be 
From first equation of motion we know that
v = u+at
So 
So final velocity will be -9.28 m/sec
Answer:
27 cm squared
Explanation:
have a good rest of ur day
The initial velocity of Ms. Stafford is

, while her acceleration is

This is a uniform accelerated motion, so we can calculate the total distance travelled by Ms. Stafford in a time of

using the law of motion for a uniform accelerated motion: