You need to use the formula--> P1V1= P2V2 (Boyles's law)
P1= 14 bar
V1= 312 mL
P2= ?
V2= 652 mL
now we plug the values into the formula.
(14 x 312) = (P2x 652)
P2= (14 x 312)/ 652= <span>6.70 bar</span>
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Answer:
13.92 %
Explanation:
Mass of
= 12.5221 g
Molar mass of
= 233.43 g/mol
The formula for the calculation of moles is shown below:
Thus,
Moles of
= 0.0536 moles
According to the given reaction,

1 mole of
is formed from 1 mole of 
Thus,
0.0536 moles of
is formed from 0.0536 moles of 
Moles of
= 0.0536 moles
Moles of sulfur in 1 mole
= 1 mole
Moles of sulfur in 0.0536 mole
= 0.0536 mole
Molar mass of sulfur = 32.065 g/mol
Mass = Moles * Molar mass = 0.0536 * 32.065 g = 1.7187 g
Mass of ore = 12.3430 g
Mass % =
=
= 13.92 %