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german
4 years ago
8

How many moles of gas are contained in a rigid, sealed, 5 L container, at 1 atm of pressure and 22 oc?

Chemistry
1 answer:
bulgar [2K]4 years ago
3 0

Rearrange the Ideal Gas Law to this:

n = PV / RT

Substitute values into the equation:

<span>n = [ (750.0 mmHg / 760.0 mmHg atm¯1) (0.890 L) ] / (0.08206 L atm mol¯1 K¯1) (294.0 K)</span>
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Please help, thanks!
Anastasy [175]
You need to use the formula--> P1V1= P2V2 (Boyles's law)

P1= 14 bar
V1= 312 mL
P2= ?
V2= 652 mL

now we plug the values into the formula.

(14 x 312) = (P2x 652)

P2= (14 x 312)/ 652= <span>6.70 bar</span>
5 0
3 years ago
Please hurry which statement is a scientist most likely to use in describing work
sashaice [31]
B i think ye ghhhjhhjjjkxhb
7 0
3 years ago
How many neutrons does the isotope N-14 have? 6 7 8 9
hodyreva [135]

Answer:

THe answer is 7

Explanation:

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7 0
3 years ago
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makvit [3.9K]

Answer:

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Explanation:

7 0
3 years ago
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The sulfur content of an ore is determined gravimetrically by reacting the ore with concentrated nitric acid and potassium chlor
katen-ka-za [31]

Answer:

13.92 %

Explanation:

Mass of BaSO_4 = 12.5221 g

Molar mass of BaSO_4 = 233.43 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{12.5221\ g}{233.43\ g/mol}

Moles of BaSO_4 = 0.0536 moles

According to the given reaction,

Ba^{2+}_{(aq)}+SO_4^{2-}_{(aq)}\rightarrow BaSO_4_{(s)}

1 mole of BaSO_4 is formed from 1 mole of SO_4^{2-}

Thus,

0.0536 moles of BaSO_4 is formed from 0.0536 moles of SO_4^{2-}

Moles of SO_4^{2-} = 0.0536 moles

Moles of sulfur in 1 mole SO_4^{2-} = 1 mole

Moles of sulfur in 0.0536 mole SO_4^{2-} = 0.0536 mole

Molar mass of sulfur = 32.065 g/mol

Mass = Moles * Molar mass = 0.0536 * 32.065 g = 1.7187 g

Mass of ore = 12.3430 g

Mass % = \frac{Mass\ of\ Sulfur}{Mass_{ore}}\times 100 = \frac{1.7187}{12.3430}\times 100 = 13.92 %

3 0
4 years ago
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