Which action do reactant molecules perform when they create chemical reactions?

If the concentration of the stock (provided) Cu(NH3)42 was 0.041 M, what concentration will the Cu2 be in beaker?

kodGreya [7K]

Answer:

$[Cu^{2+}]=0.041 M$

Explanation:

Hello!

In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:

$[Cu^{2+}]=0.041\frac{molCu(NH_3)_4^{2+}}{L}*\frac{1molCu^{2+}}{1molCu(NH_3)_4^{2+}} =0.041 \frac{molCu(NH_3)_4^{2+}}{L}$

$[Cu^{2+}]=0.041 M$

Best regards!

6 0

3 years ago

A 2.00 L sample of gas at 35C is to be heated at constant pressure until it reaches a volume of 5.25 L. To what Kelvin temperatu

Anastaziya [24]

Answer:

The sample will be heated to 808.5 Kelvin

Explanation:

Step 1: Data given

Volume before heating = 2.00L

Temperature before heating = 35.0°C = 308 K

Volume after heating = 5.25 L

Pressure is constant

Step 2: Calculate temperature

V1 / T1 = V2 /T2

⇒ V1 = the initial volume = 2.00 L

⇒ T1 = the initial temperature = 308 K

⇒ V2 = the final volume = 5.25 L

⇒ T2 = The final temperature = TO BE DETERMINED

2.00L / 308.0 = 5.25L / T2

T2 = 5.25/(2.00/308.0)

T2 = 808.5 K

The sample will be heated to 808.5 Kelvin

7 0

4 years ago

Can yall assist me with this lab? It is really screwing me up... No spam!! the only part that I need is the last page. I will ma

Nadusha1986 [10]

Answer:

You can block me I don't care ;-; Ive actually been wanting to be blocked because I don't want my account on brainly anymore but they cant understand that I used my school email for this account and my school email doesnt reseave emails not from the school and I cant change the email to a different one so I cant reset my password so I cant delete my account..

Explanation:

6 0

3 years ago

Using the following equation

Valentin [98]

Thermal energy when solid, liquor , and gas combine

7 0

3 years ago

Read 2 more answers

Calculate the percent yield if 52.9 g of ethanol reacts to produce 26.7 g of ether.

blagie [28]

Answer:

The % yield is 62.7 %

Explanation:

Step 1: the balanced equation

2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(l)

Step 2: Data given

mass of ethanol = 52.9 grams

molar mass of ethanol = 46.07 g/mol

mass of ether = 26.7 grams

Molar mass of ether = 74.12 g/mol

Step 3: Calculate moles of ethanol

Number of moles = Mass / molar mass

Moles of ethanol = 52.9 grams / 46.07 g/mol

Moles of ethanol = 1.15 moles

Step 4: Calculate moles of ether

For 2 moles of ethanol consumed, we have 1 mole of ether produced

For 1.15 moles of ethanol consumed, we have 1.15/2 = 0.575 moles of ether produced

Step 5: Calculate mass of ether

Mass = moles * Molar mass

Mass ether = 0.575 moles * 74.12 g/mol = 42.62 grams = theoretical yield

Step 6: Calculate % yield

% yield = (26.7 / 42.62) * 100 = 62.7%

The % yield is 62.7 %

6 0

4 years ago