Answer:
3.63m/s²
Explanation:
Given parameters:
Mass of box = 8kg
Net force = 29N
Unknown:
Acceleration of the box = ?
Solution:
To solve this problem, we use Newton's second law of motion which is stated as;
Force = mass x acceleration
Acceleration = =
Acceleration = 3.63m/s²
Answer : The for this reaction is, -88780 J/mole.
Solution :
The balanced cell reaction will be,
Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.
The half oxidation-reduction reaction will be :
Oxidation :
Reduction :
Now we have to calculate the Gibbs free energy.
Formula used :
where,
= Gibbs free energy = ?
n = number of electrons to balance the reaction = 2
F = Faraday constant = 96500 C/mole
= standard e.m.f of cell = 0.46 V
Now put all the given values in this formula, we get the Gibbs free energy.
Therefore, the for this reaction is, -88780 J/mole.
Answer:
There are
Explanation:
In this problem, we need to find the number of molecules in mol of
.
The molar mass of is
No of moles = mass/molar mass
We can find mass from above formula.
Also,
No of moles = no of molecules/Avogadro number
Hence, there are