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bija089 [108]
3 years ago
11

Please help me! I need help.

Mathematics
1 answer:
pashok25 [27]3 years ago
4 0

Answer:

a= 40

Step-by-step explanation:

you just add the other two angles , then subtract the number you get from 180 . this is so since every  triangle has to equal 180 . and the squares that you see equal 90 degrees .

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Simplify<br> CLEAR Step By Step Explanation Please. <br> Will Mark Brainliest
siniylev [52]

Answer:

1/x+5

Step-by-step explanation:

1. Rewrite 3x as a difference

x-2/x^2 + 5x-2 - 10

2. Factor out x from the equation, then factor out -2.

x-2/ x+(x+5) - 2(x+5)

3. Factor out x+5 from the expression

x-2/ (x+5)(x-2)

4. Reduce the fraction with x-2

x-2 / (x+5) x-2

1/x+5

8 0
2 years ago
Heellllllllllllllpppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
iogann1982 [59]

34.76

o

, nearly.

Explanation:

Angle of elevation = arc tan( (vertical height)/(length os the shadow)).

Here, this angle is

arc tan (12.5

/

18) =

34.78

o

, nearly

6 0
3 years ago
4 1/15 round to the nearest 1000th
emmainna [20.7K]

Answer:

0.067

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The diagonals of a rectangle are always perpendicular.<br><br> A)True<br> B)False
goblinko [34]

Answer:

Step-by-step explanation:

False. If L does not equal W the diagonals are not perpendicular. If L=W then they are perpendicular but that is a square and a special case which is not always true of a rectangle.

4 0
2 years ago
An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
8090 [49]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by  

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

t= \frac{-80\pm \sqrt{6400+19200}}{-32}

t= \frac{-80\pm \sqrt{25600}}{-32}  

Simplify:

t = -\frac{5}{2} = -2.5 sec and t = \frac{15}{2} = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec


6 0
3 years ago
Read 2 more answers
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