Step-by-step explanation:
Lets first find the remainder when p(x) is divided by x-2
p(2)=2(2)³+b(2)²+3(2)-5
p(2)=16+4b+6-5
p(2)=4b+17
Now let's find the remainder when q(x) is divided by x-2
q(2)=(2)³+(2)²-4(2)-b
q(2)=8+4-8-b
q(2)=4-b
Now let's equate both of them
4b+17=4-b
4b+b=4-17
5b=-13
b=-13/5 as required
Rudy answered 2 more questions correctly
...........
46x2=92
44x2=88
...........
92-88=4
Answer:
Therefore you can wear your rings in =336 ways
Step-by-step explanation:
Multiplication Law: If one occurs in x ways and second event occurs in y ways.Then the number of ways that two event occur in sequence is xy
Given that you have 3 different rings.
We have total 10 figures.
But you don't wear ring on your thumbs.
We have 2 thumbs.
So you can wear rings on (10-2) = 8 figures.
The ways of wearing of first ring is = 8
The ways of wearing of second ring is = 7
The ways of wearing of third ring is = 6
Therefore you can wear your rings in =(8×7×6)
=336 ways
It would be sometimes because it can be 82.2% but if you round it the closest one would be 80% if it was 84.7% its closer to 85 so it would be 85% I hope I helped you out rate the answer if I got it right thanks!
We have that
<span>If (5x-4+13x=5) --------------> then x=1/2
Step 1
</span>let's substitute the value of x = (1/2) in the expression [5x-4+13x] and verify its result
5*(1/2)-4+13*(1/2)
(5/2)-4+(13/2)
(5-4*2+13)/2----------> (5-8+13)/2=10/2=5
then
5=5-----------> <span>the value of x = (1/2) satisfies equality</span>