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liberstina [14]
3 years ago
12

Two angles are supplementary. They are represented by (3x)° and (12x+1)°. Find both angles.

Mathematics
1 answer:
klio [65]3 years ago
7 0

Answer:

35.8°

144.2°

Step-by-step explanation:

Definition of Supplementary Angles: They add up to 180°

Step 1: Set up equation

3x + 12x + 1 = 180

Step 2: Solve

15x + 1 = 180

15x = 179

x = 11.93

Step 3: Find angles

∠1 = 3x

m∠1 = 3(11.93) = 35.8°

∠2 = 12x + 1

m∠2 = 12(11.93) + 1 = 144.2°

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Burt's grandparents started a savings account for him when he was born. They invested
SashulF [63]

Answer:

4594.76 USD will be in the account on Burt's 18th birthday.

Step-by-step explanation:

Since interest rate is constant in time, we can use the definition of composite interest to determine how much money will be on Burt's 18th birthday, that is:

C = C_{o}\cdot \left(1+\frac{r}{100} \right)^{t} (1)

Where:

C_{o} - Initial amount, measured in US dollars.

C - Current amount, measured in US dollars.

r - Annual interest rate, measured in percentage.

t - Time, measured in years.

If we know that C_{o} = 1250\,USD, r = 7.5 and t = 18, then the money in the savings account on Burt's 18th birthday is:

C = (1250\,USD)\cdot \left(1+\frac{7.5}{100} \right)^{18}

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3 years ago
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USPshnik [31]

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4 years ago
What is the vertex of the function f (x) = x2 - 10x?<br>(5,-25)<br>(5.-75)<br>(-5,75)<br>(-5,25)​
JulsSmile [24]

Option A

The vertex is (h, k) = (5, -25)

<em><u>Solution:</u></em>

<em><u>Given function is:</u></em>

f(x) = x^2-10x

<em><u>The vertex form is given as:</u></em>

y = a(x-h)^2+k

<h3>where (h, k) is the vertex</h3>

Rewrite the equation in vertex form

f(x) = x^2-10x

Complete the square for  x^2-10x

Use the form ax^2+bx+c to find the values of  a, b, c

a = 1 , b = -10, c = 0

Consider the vertex form of a parabola

a(x+d)^2+e

Substitute the values of a and b into the following formula to find "d" :

d = \frac{b}{2a}\\\\d = \frac{-10}{2 \times 1}\\\\d = -5

Find the value of "e" using the formula,

e = c - \frac{b^2}{4a}\\\\e = 0 - \frac{(-10)^2}{4 \times 1}\\\\e = -25

Substitute the value of a, d, e into vertex form

a(x+d)^2+e\\\\1(x-5)^2-25\\\\(x-5)^2-25

Set y equal to above equation

y = (x-5)^2-25

Compare the above equation with vertex form

y = a(x-h)^2+k

y = (x-5)^2-25

We find, h = 5 and k = -25

Thus the vertex is (h, k) = (5, -25)

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