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Luden [163]
4 years ago
5

How many atoms are represented by one formula unit of aluminum carbonate A12(CO2)3

Chemistry
2 answers:
guapka [62]4 years ago
6 0

Answer:

14 atoms

Explanation:

ad-work [718]4 years ago
5 0

Answer:

well ,if I have done my sum rights there are

14 atom in the one formula unit of aluminium carbonate.

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Nitrogen is a group 15 element. What does being In this group imply about the structure of the nitrogen atom?
sveticcg [70]

Answer:

Nitrogen has 5 valence electrons

Explanation:

nitrogen has it's attoms form triple bonds which are very hard to break

so non-reactive

4 0
3 years ago
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How much of sliver metal will weight exactly 2500.0
grandymaker [24]

The density of silver is 10.5 g/cm3.

8 0
3 years ago
When a compound donates (loses) electrons, that compound becomes oxidized. Such a compound is often referred to as an electron d
rjkz [21]

Assuming this is a true or false question, the answer would be True

3 0
3 years ago
Given that the free energy of the twist-boat conformer of cyclohexane is 5.3 kcal/mol greater than that of the chair conformer,
marishachu [46]

Answer:

0.013%

Yes, it does. The answer agrees with the statement.

Explanation:

Both conformers are in equilibrium, and it can be represented by the equilibrium equation K:

K = [twist-boat]/[chair]

The free energy between them can be calculated by:

ΔG° = -RTlnK

Where R is the gas constant (8.314 J/mol.K), and T is the temperature (25°C + 273 = 298 K).

ΔG° = 5.3 kcal/mol * 4.182 kJ/kcal = 22.165 kJ/mol = 22165 J/mol

22165 = -8.314*298*lnK

-2477.572lnK = 22165

lnK = -8.946

K = e^{-8.946}

K = 1.30x10⁻⁴

[twist-boat]/[chair] = 1.30x10⁻⁴

[twist-boat] = 1.30x10⁻⁴[chair]

The percentage of the twist-boat conformer is:

[twist-boat]/([twist-boat] + [chair]) * 100%

1.30x10⁻⁴[chair]/(1.30x10⁻⁴[chair] + [chair]) *100%

0.013%

The statement about the conformers is that the chair conformer is more stable, and because of that is more present. So, the answer agrees with it.

3 0
3 years ago
0.68 moles of calcium to calcium atoms​
Oksanka [162]

0.68 \: moles \: calcium \times  \frac{6.02 \times  {10}^{23} \: calcium \: atoms }{1 \: mole \: calcium} \\

The (( mole calcium ))s are simplified so the answer is based on the number of calcium atoms.

0.68 \times 6.02 \times  {10}^{23} = 68 \times  {10}^{ - 2} \times 602 \times  {10}^{ - 2} \times  {10}^{23} \\

= 68 \times 602 \times  {10}^{ - 4} \times  {10}^{23} = 40936 \times  {10}^{19} \\

calcium \: atoms = 40936 \times  {10}^{19}  \\

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

3 0
3 years ago
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