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ikadub [295]
3 years ago
11

You have 168 ride tickets. You need 4 tickets to ride the Ferris wheel and 8 tickets to ride the roller Coaster. You ride both r

ides a total of 26 times. How many times did you ride the roller coaster?
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
8 0

You ride the roller coaster 8 times.

Step-by-step explanation:

Step 1; You need 4 tickets to ride the Ferris wheel and 8 tickets to ride the roller coaster. You have been on the Ferris wheel 26 times.

Tickets needed to ride Ferris wheel = 4 tickets,

Tickets needed to ride the roller coaster = 8 tickets.

Tickets spent riding the Ferris wheel = tickets to ride the Ferris wheel × Number of times on the Ferris wheel = 8 tickets × 26 times = 104 tickets.

Step 2; We need to calculate the number of remaining tickets and how many times I can ride the roller coaster.

Remaining tickets = 168 - 104 = 64 tickets.

Times I can ride the roller coaster = remaining tickets / tickets to ride the roller coaster

                                                           = 64 / 8 = 8 times.

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zhuklara [117]

Answer: (27- 4/3 pi) r^3

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2.  Volume of a sphere: V=4/3 pi r^3 ......

5 0
3 years ago
A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading
Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

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Force = 27085.09 N

b.

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0
3 years ago
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IrinaVladis [17]

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To find the gradient is a little more tricky, but we can follow the formula:

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So we sub in our values:

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