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3 years ago

The temperature of a sample of liquid water changes from 50°C to 30°C. Which statement best explains the change that must

Chemistry

2 answers:

alina1380 [7]3 years ago

7 0

Answer:

The statement which best explains the change that must happen at the molecular level is below:

Explanation:

The molecules move more slowly and their average kinetic energy decreases

kifflom [539]3 years ago

5 0

Answer:

B: The molecules move more slowly and their average kinetic energy decreases.

Explanation:

took the test

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How many grams of steam at 100 °C would be required to raise the temperature

Alex777 [14]

The mass of steam required to raise the temperature of water is 3.5 g.

The given parameters;

mass of the benzene, = 47.6
initial temperature of the benzene, = 5.5 ⁰C
final temperature of the benzene = 30 ⁰C

The molar mass of Benzene = 78.11 g/mol

The molar mass of water = 18 g/mol

The number of moles of the Benzene is calculated as follows;

$n = \frac{47.6}{78.11} = 0.61 \ mole$

The mass of steam required is calculated as follows;

heat lost by steam = heat absorbed by benzene

$\frac{m}{18} \times 40.7 \times 10^3 = 47.6(1.63)(30-5.5) \ + \ 0.61 \times 9.87 \times 10^3\\\\2261.11 m = 7921.61\\\\m = \frac{7921.61}{2261.11} \\\\m = 3.5 \ g$

Thus, the mass of steam required to raise the temperature of water is 3.5 g.

Learn more here:brainly.com/question/14963365

3 0

3 years ago

What is the amount of heat released by 1.00 gram of liquid water at 0°C when it changes to 1.00 gram of ice at 0°C?

QveST [7]

Answer:

334J/g

Explanation:

Data obtained from the question include:

Mass (m) = 1g

Specific heat of Fusion (Hf) = 334 J/g

Heat (Q) =?

Using the equation Q = m·Hf, we can obtain the heat released as follow:

Q = m·Hf

Q = 1 x 334

Q = 334J

Therefore, the amount of heat released is 334J

8 0

4 years ago

Anyone want to talk? kinda bored right now

OverLord2011 [107]

Answer:

Explanation:

7 0

3 years ago

Read 2 more answers

A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain

sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

$-w=\frac{dm}{dt}$

w is the mass flow

m is the mass of salt

$-v*C=\frac{dm}{dt}$

v is the volume flow

C is the concentration

$C=\frac{m}{V+(6-3)*L/min*t}$

$-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}$

$-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}$

$-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)$

$-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)$

$m=90kg*[2000L/(2000L+3*L/min*t)]$

a) Initially: t=0

$m=90kg*[2000L/(2000L+3*L/min*0)]=90kg$

b) t=210 min (3.5 hr)

$m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg$

c) If time trends to infinity the division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

6 0

4 years ago

Which of these oxides will likely form a colored solution when dissolved in water?

Alik [6]

Mn₂O

Explanation:

The oxide that will most likely form colored solutions is Mn₂O.

This is because most transition metals form colored compounds. Manganese is a transition metal belonging to the d-block on the periodic table.

Other examples of transition metals are scandium, titanium, iron, copper, cobalt, nickel, zinc
They belong to the d-block on the periodic table.
They have variable oxidation states.
Most of their solutions are always colored.

Learn more:

Periodic table brainly.com/question/8543126

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7 0

4 years ago