Answer:
I am confused what is the question?
Answer:
Q1: 12.5
Q3: 16
IQR: 3.5
Step-by-step explanation:
Mean : 14.25
Median : 13.5
Mode : 13, 12
Range: 6
Minimum :12
Maximum: 18
Count n: 8
Sum: 114
Quartiles Quartiles:
Q1 --> 12.5
Q2 --> 13.5
Q3 --> 16
Interquartile
Range IQR: 3.5
Outliers: none
For this case we must solve the following equation:

We apply distributive property on the right side of the equation:

We subtract 6y on both sides of the equation:

We subtract 6 from both sides of the equation:

Dividing by 6 on both sides of the equation:

So, the result is 
Answer:

Answer:
The mass of the ice block is 2116 grams ⇒ a
Step-by-step explanation:
The formula of density is
, where m is the mass and V is the volume
To find the mass from this formula multiply both sides by V,
then m = p.V
∵ The density of ice is approximately 0.92 g/cm³
∴ p = 0.92
- That means the mass of 1 cm³ is 0.92 g
∵ The volume of an ice block is 2300 cm³
∴ V = 2300
- Use the formula of the mass
∵ m = p.V
- Substitute the values of p and V in it
∴ m = (0.92)(2300)
∴ m = 2116 grams
The mass of the ice block is 2116 grams
Answer:
3.4-1.85 = 1.55 3.4+1.55=4.95
Step-by-step explanation: