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aksik [14]
3 years ago
8

The expression (2x^2)^3 is equivalent to

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
7 0

Answer:

8x^6

Step-by-step explanation:

gregori [183]3 years ago
7 0

Answer:

8x^6

Step-by-step explanation:

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A city grid of Anytown, USA is shown on the grid below. The fire department is represented by quadrilateral RSTU. Another fire d
Alekssandra [29.7K]
Answer: option d. C (0,3), D (0,5).

Justification:

1) The x - coordinates of the vertices A and B are shown in the diagrama, They are both - 4, so the new vertices C and D must be in a line parallel to y = - 4.

2) The y-coordinates of the  vertices A and B are also shown in the diagrama. They  are equal to 3 and 5 respectively.

3) We can see that the new points C and D must be over a parallel line to y = - 4 and that their distance to the points A and B has to be the same distance of the point R and S to U and T.

That distance is 4, so the line may be y = - 7 or y = 0.

4) If the line is y = 7 the points C and D would have coordinates (-7,3) and (-7,5), but this points are not among the options.

5) If the line is y = 0 the points C and D would have coordinates (0, 3) and (0,5), which is precisely the points of the option d. That is the answer.



3 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bx%7D%20%20-%20%20%20%7B3%7D%5E%7Bx%7D%20%20%3D%20%20%20%20%5Csqrt%7B%20%7B6%7D
strojnjashka [21]

Answer:

x = 0

Step-by-step explanation:

{2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {9}^{x } } \\  \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {( {3}^{2}) }^{x } } \\  \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {({3)}^{2x}}}\\  \\ {2}^{x} -  \cancel{{3}^{x}} = \sqrt{ {6}^{x} } - \cancel{ {3}^{x} } \\  \\ {2}^{x} = \sqrt{ {6}^{x} } \\ squaring \: both \: sides \\  \\  {( {2}^{x} )}^{2}  =  {(\sqrt{ {6}^{x} })}^{2}  \\  \\  {2}^{2x}  =  {6}^{x}  \\  \\   {2}^{2x}  =  {(2 \times 3)}^{x}  \\  \\   {2}^{2x}  =  {2 ^{x}  \times 3}^{x}  \\  \\  \frac{ {2}^{2x}  }{ {2}^{x}  } =  3^{x}  \\  \\   {2}^{2x - x}  =  {3}^{x}  \\  \\  {2}^{x}  =  {3}^{x}  \\  \\   \frac{ {2}^{x} }{ {3}^{x} }  = 1 \\  \\  \bigg(  \frac{2}{3} \bigg)^{x}  = 1 \\  \\  \implies \: x = 0 \\  \\  \because \: for \: x = 0 \\  \\ \bigg(  \frac{2}{3} \bigg)^{0}  = 1

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3 years ago
Which statement is false?
oee [108]
I believe it’s the last one
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Sasha baked 21 cookies with 3 scoops of flour. How many scoops of flour does Sasha need in order to bake 28 cookies? Solve using
aniked [119]
4 because 21 is 3x7 and 28 is 4x7
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What is the difference between constructing a square and constructing a regular hexagon?
dexar [7]

Answer:

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.Step-by-step explanation:

5 0
2 years ago
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