Answer:
9.6 m
Explanation:
This is a case of motion under variable acceleration . So no law of motion formula will be applicable here. We shall have to integrate the given equation .
a = 3.6 t + 5.6
d²x / dt² = 3.6 t + 5.6
Integrating on both sides
dx /dt = 3.6 t² / 2 + 5.6 t + c
where c is a constant.
dx /dt = 1.8 t² + 5.6 t + c
when t = 0 , velocity dx /dt is zero
Putting these values in the equation above
0 = 0 +0 + c
c = 0
dx /dt = 1.8 t² + 5.6 t
Again integrating on both sides
x = 1.8 t³ / 3 + 5.6 x t² /2 + c₁
x = 0.6 t³ + 2.8 t² + c₁
when t =0, x = 0
c₁ = 0
x = 0.6 t³ + 2.8 t²
when t = 1.6
x = .6 x 1.6³ + 2.8 x 1.6²
= 2.4576 + 7.168
= 9.6256
9.6 m
Answer:1.039 N
Explanation:
Given
inclination of tray
gravitational Force=5 N
Now this gravitational force has two component i.e.
is parallel to the tray =1.039 N
is perpendicular to the tray =4.890 N
Answer:
the horizontal force acting on rod is - 25.909 N
veritical force is 25.48 N
Explanation:
Given data:
mass of rod is m 2.6 kg
length of rod is 1.5 m
Hinge distance from the wire is 0.70 m
Apply torque law about hinge
Tension in the wire is
![T = \frac{[\frac{1.5}{2} cos 28 ]2.6 \times 9.8}{0.70}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B%5B%5Cfrac%7B1.5%7D%7B2%7D%20cos%2028%20%5D2.6%20%5Ctimes%209.8%7D%7B0.70%7D)
= -25.909 N
the horizontal force acting on rod is
Fx = T
FX = - 25.909 N
vertical force is
Fy = mg
The final speed of the nickel at the given quantity of heat is determined as 202.1 m/s.
<h3>Final speed of the nickel</h3>
Apply the principle of conservation of energy.
Q = mcΔθ
Q = (18)(0.444)(66 - 20)
Q = 367.63 J
Q = K.E = ¹/₂mv²
2K.E = mv²
v = √(2K.E/m)
where;
v = √(2 x 367.63)/(0.018))
v = 202.1 m/s
Learn more about speed here: brainly.com/question/4931057
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