Answer:
The magnitude of the electric field at a point equidistant from the lines is 
Explanation:
Given that,
Positive charge = 24.00 μC/m
Distance = 4.10 m
We need to calculate the angle
Using formula of angle



We need to calculate the magnitude of the electric field at a point equidistant from the lines
Using formula of electric field

Put the value into the formula



Hence, The magnitude of the electric field at a point equidistant from the lines is 
Answer:
Density = Mass/volume. D= 60/30.Divide it and you'll get ur answer as 2
The degree is 4678% to pass theough all membranes.
Answer: b
Explanation:
B is a chemical property
Reference what are physical properties
And what are chemical properties
Under certain conditions it can release a gas is the key words letting you know this is a chemical property
Answer:
Centripetal acceleration
Explanation:
- The centripetal acceleration is the motion inwards towards the center of a circular path.
- <em><u>Centripetal acceleration is given by; the square of the velocity, divided by the radius of the circular path.
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ac = v²/r
Where; ac = acceleration, centripetal, m/s², v is the velocity, m/s and r is the radius, m