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ololo11 [35]
3 years ago
6

HURRY!!

Physics
2 answers:
JulijaS [17]3 years ago
8 0

Electrons move. I got you

QveST [7]3 years ago
5 0

Its C just checked on edg

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Newton's laws of motion works well for ordinary situations on earth. However, these laws of motion do not work for all cases. In
Alenkasestr [34]

Newton's second law of motion pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

And the correct answer is A) on the surface of the moon; because Newton's second law provides the explanation for the behavior of objects upon which the forces do not balance. The law states that unbalanced forces cause objects to accelerate with an acceleration that is directly proportional to the net force and inversely proportional to the mass.

So the correct answer is A) on the surface of the moon

Hope I helped.

5 0
3 years ago
Which statement is true for electric field lines?
KiRa [710]
The best answer is D. field lines should always be crossing each other.
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3 years ago
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What is the resultant of the two vectors shown?
BARSIC [14]

Answer:

B is the right answer of the following statement

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3 years ago
Best for growing most plants, which soil has good drainage and sufficient moisture?
hammer [34]
The correct answer is "loam".
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3 years ago
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A planet has been observed orbiting a nearby star. This star has a mass of 3.5 solar masses, and the planet is 4.2 AU from the s
kondaur [170]

Answer:

4.6 years

Explanation:

This is solved using Kepler's third law which says:

T^2=\frac{4\pi ^2}{GM} a^2

Where

T = Orbital period of the planet (in seconds)

a = Distance from the star (in meters)

G = Gravitational constant

M = Mass of the parent star (in kg)

From the information given

M = 3.5M_{sun} = 6.96*10^{30} kg

a=4.2AU = 6.28*10^{11} meters

G = 6.67*10^{-11}m^3kg^{-1}s^{-2}

We put this into Kepler's law and get:

T=\sqrt{\frac{4\pi ^2}{6.67*10^{-11}*6.96*10^{30}} (6.28*10^{11})^3}=145,128,196 seconds.

This when converted to years is 4.6 years.

4 1
2 years ago
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