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Aleonysh [2.5K]
3 years ago
7

The acceleration of an object as a function of time is given by a(t) = (1.00 m/s2)t2. If displacement of the object between time

and time t = 2.00 s is 15.0 m, what is the velocity of the object at time t = 0.00 s?
a-13.5 m/s
b-Not enough information is given to determine the velocity of the object at time t = 0.00 s.
c-6.25 m/s
d-3.75 m/s
1.25 m/s
Physics
1 answer:
jolli1 [7]3 years ago
3 0

not enough information is given to determine the velocity of the object at time to=0.00s

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answers At the beginning of 2019, Robotics Inc. acquired a manufacturing facility for $12.3 million. $9.3 million of the purchas
pshichka [43]

Answer:

$613,077

Explanation:

Calculation for the depreciation on the building for 2021

First step is to calculate the depreciation expense for the year 2019 and 2020 using this formula

Depreciation expense = (Purchase price - Residual value) ÷ (Useful life)

Let plug in the formula

Depreciation expense= ($9,300,000 - $1,300,000) ÷ (20 years)

Depreciation expense= ($8,000,000) ÷ (20 years)

Depreciation expense= $400,000

Second step is to calculate the book value for the year 2021 using this formula

Book value = Purchase price - Depreciation expenses *2 years

Let plug in the formula

Book value= $9,300,000 - $400,000 × 2

Book value= $8,500,000

Last step is to calculate the depreciation for 2021 using this formula

2021 Depreciation=(Book value-Residual value)÷Useful life

2021 Depreciation= ($8,500,000 - $530,000) ÷ (15 years - 2 years)

2021 Depreciation=$7,970,000÷13 years

2021 Depreciation= $613,077

Therefore the depreciation on the building for 2021 will be $613,077

8 0
2 years ago
One end of a spring with a force constant of k = 10.0 N/m is attached to the end of a long horizontal frictionless track and the
koban [17]

Answer:

-2.478

0.379

11.14

24.78

Explanation:

Angular frequency of spring in harmonic motion is given by?

ω = √(k/m)

ω = √(10/2.2)

ω = √4.54

ω = 2.13 s^-1

If at t=0 the mass is in negative amplitude (x = -A = -2.48 m) then we describe the position with negative cosine

x(t) = -A * cos(ωt)

x(t) = -2.48 * cos(2.13 * 1)

x(t) = -2.48 * 0.9993

x(t) = -2.478

Velocity and acceleration are 1st and 2nd derivative of position

b)

v(t) = Aω * sin(ωt)

v(t) = 2.48 * 2.13 * sin(2.13 * 1)

v(t) = 5.282 * sin2.13

v(t) = 5.282 * 0.03717

v(t) = 0.379 m/s

c)

a(t) = Aω^2 * cos(ωt)

a(t) = 2.48 * 2.12² * cos(2.13 * 1)

a(t) = 2.48 * 4.494 * cos2.13

a(t) = 11.15 * 0.9993

a(t) = 11.14 m/s²

d)

F = -k * x(t)

F = -10 * -2.478

F = 24.78 N

3 0
2 years ago
Three identical springs, each with stiffness 1200 N/m are attached in series (that is, end to end) to make a longer spring to ho
OLga [1]
<h2>Answer:</h2>

400N/m

<h2>Explanation:</h2>

When n identical springs of stiffness k, are attached in series, the reciprocal of their equivalent stiffness (1 / m) is given by the sum of the reciprocal of their individual stiffnesses. i.e

\frac{1}{m} = ∑ⁿ₁ [\frac{1}{k_{i}}]          -----------------------(i)

That is;

\frac{1}{m} = \frac{1}{k_{1}} + \frac{1}{k_{2}} + \frac{1}{k_{3}} + . . . + \frac{1}{k_{n}}      -------------------(ii)

If they have the same value of stiffness say s, then equation (ii) becomes;

\frac{1}{m} = n x \frac{1}{s}           -----------------(iii)

Where;

n = number of springs

From the question,

There are 3 identical springs, each with stiffness of 1200N/m and they are attached in series. This implies that;

n = 3

s = 1200N/m

Now, to calculate the effective stiffness,m, (i.e the stiffness of a longer spring formed from the series combination of these springs), we substitute these values into equation (iii) above as follows;

\frac{1}{m} = 3 x \frac{1}{1200}

\frac{1}{m} = \frac{3}{1200}

\frac{1}{m} = \frac{1}{400}

Cross multiply;

m = 400N/m  

Therefore, the stiffness of the longer spring is 400N/m

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3 years ago
A roller skate coming to a stop because of
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Answer:

Laws of the Park: Newton's First Law

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Explanation:

Hope this helps..

8 0
2 years ago
A factor that influences your resting metabolic rate is
krok68 [10]

Gender....................

3 0
2 years ago
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