All categories

3 years ago

What are the values of x and y for which quadrilateral is ABCD is a parallelogram? Explain.

Mathematics

1 answer:

Mrac [35]3 years ago

6 0

Answer:

The value of x = 2.

The value of y = 1.

Step-by-step explanation:

The length of opposite sides of a parallelogram are equal.

Hence, the length of 4x - 3 and x + 3 are equal.

Similarly, the lengths of 3y and 5y - 2 are equal.

$\therefore 4x - 3 = x + 3$

$\implies 3x = 6$

$\implies \textbf{x = 2}$

And $3y = 5y - 2$

$2y = 2$

$\implies \textbf{y = 1}$

Therefore, the values of x and y are: 2; 1 respectively.

You might be interested in

Deserts cover about = of all the land

NeX [460]

Answer: Deserts cover one-third, of the Earth's total landmass.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A rectangular restaurant kitchen has a perimeter of 36 meters and an area of 80 square meters. what are the dimensions of the ki

konstantin123 [22]

Let L and W be the length and width of the given rectangle, respectively. Perimeter is calculated through the equation,

P = 2L + 2W

Substituting the perimeter,
36 = 2L + 2W
Simplifying,
18 = L + W

The area is calculated by multiplying the length and width as below,
A = 80 = LW

Substituting the expressions,
80 = (L)(18 - L)
The value of L from the equation is 8. With this, the value of W is equal to 10.

Therefore, the dimensions of the rectangle are 8 m by 10 m.

8 0

3 years ago

What is the answer I'm so stuck this is so hard for dumb people like me helpppppppp

miskamm [114]

Well I don't remember the equation with all the numbrical stuff but if you times 5 and 5 than times 4 and 5 which is 25 and 20 take 20 away from 25 and you have your answer hope it helps

4 0

3 years ago

A rectangle has a length of (x + 4) centimeters and a width of 12x centimeters. If the perimeter is 26 centimeters, what is the

STALIN [3.7K]

Answer:

The width of rectangle is $W=\frac{108}{13}\ cm$ or $8\frac{4}{13}\ cm$

Step-by-step explanation:

we know that

The perimeter of rectangle is equal to

$P=2(L+W)$

where

L is the length of rectangle

W is the width of rectangle

we have

$P=26\ cm\\L=(x+4)\ cm\\W=12x\ cm$

substitute

$26=2(x+4+12x)$

solve for x

$26=2(13x+4)$

$26=26x+8$

$26x=26-8$

$26x=18$

$x=\frac{18}{26}$

simplify

$x=\frac{9}{13}$

<em>Find the width of rectangle</em>

$W=12x\ cm$

substitute the value of x

$W=12(\frac{9}{13})=\frac{108}{13}\ cm$

Convert to mixed number

$\frac{108}{13}\ cm=\frac{104}{13}+\frac{4}{13}=8\frac{4}{13}\ cm$

7 0

3 years ago

If 1000 square centimeters of material is available to make a box with a square base and an open top, find the largest possible

guapka [62]

<span>The area of the base is x^2> The height is h. Each side of the box has area xh. There are 4 sides of the box so the total surface area of the box is x^2+4xh and that is equal to 1000. Solve that equation for h: x^2+4xh = 1000 h = (1000-x^2)/4x so the Volume = x^2[(1000-x^2)/4x] Simplify and get V = 250x-x^3/4 The volume will be a maximum when its first derivative is 0. V' = 250-3/4x^2 Set to 0 and solve. x=18.26 Now plug into the volume function to find the maximum volume: V=250(18.26)-(18.26)^3/4 V= 4564.35 - 1522.10 =3042.25</span>

6 0

3 years ago

Read 2 more answers