Area of the shaded region
square cm
Perimeter of the shaded region
cm
Solution:
Radius of the quarter of circle = 12 cm
Area of the shaded region = Area of quarter of circle – Area of the triangle



square cm.
Area of the shaded region
square cm
Using Pythagoras theorem,



Taking square root on both sides of the equation, we get
cm
Perimeter of the quadrant of a circle = 

cm
Perimeter of the shaded region =
cm
cm
Hence area of the shaded region
square cm
Perimeter of the shaded region
cm
Answer:

Step-by-step explanation:
<u>Equation Solving</u>
We are given the equation:

It's required to solve the equation for D. All letters must preserve their capitalization.
We must isolate the letter D by removing from the left side all the terms and coefficients that surround it.
Adding 7:

Dividing by f:

Answer:

Explanation:
Let's begin writing down everything
(X×(-11)+5)×(-9)+X-55
Now we can multiply
-9(-11X+5)+X-55
99X-45+X-55
And so we get
100X-100
Factorize 100
100(x-1)
Answer:
x=14
y=27
z=43
Step-by-step explanation:
hope it helps!
Answer: D. (4,3)
The x coordinates of A and B are 9 and -1 in that order. Add them up to get 9+(-1) = 9-1 = 8. Then divide by two to end up with 8/2 = 4. The midpoint has an x coordinate of 4.
Repeat for the y coordinates. Add them up: 8+(-2) = 8-2 = 6. Then divide by two: 6/2 = 3. The midpoint has an y coordinate of 3.
Those two coordinates pair up to get (x,y) = (4,3) which is the midpoint of segment AB.