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3 years ago

7

Every day Jordan is paid an hourly wage plus a flat fee for transportation expenses based on the graph how much is Jordan paid p

er hour?

2 answers:

Dovator [93]3 years ago

8 0

That’s my name and we can’t see graph sry man

melisa1 [442]3 years ago

8 0

Answer:

$15

Step-by-step explanation:

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Sean b= 5,79; c= 10,4,el angulo A= 54,46°, el angulo C mide ?

Rzqust [24]

Answer:

$C \approx 91.732^{\circ}$

Step-by-step explanation:

(This exercise is presented in Spanish and for that reason explanation will be held in such language)

El lado restante se determina por la Ley del Coseno:

$a = \sqrt{b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A}$

$a = \sqrt{5.79^{2}+10.4^{2}-2\cdot (5.79)\cdot (10.4)\cdot \cos 54.46^{\circ}}$

$a \approx 8.466$

Finalmente, el angulo C se halla por medio de la misma ley:

$\cos C = - \frac{c^{2}-a^{2}-b^{2}}{2\cdot a \cdot b}$

$\cos C = -\frac{10.4^{2}-8.466^{2}-5.79^{2}}{2\cdot (8.466)\cdot (5.79)}$

$\cos C = -0.030$

$C \approx 91.732^{\circ}$

3 0

3 years ago

Multiply. (2.5 times 10^-8) (9 times 10^-10)

Lorico [155]

The complete answer is 2.25E-17

but I think it may be A

8 0

3 years ago

Exterior Angles of A Triangle

gladu [14]

The exterior angle is supplementary to the adjacent angle (they form a linear pair) and is the sum of the two angles in the triangle that are not adjacent to it. For example, in number 2, the exterior angle is 28+40=68 degrees. You can use the other method to check. 68 degrees is supposed to be in a linear pair with 112 degrees, which it is. So the answer to number 2 would be 68 degrees.

Try doing this for the rest of them

7 0

2 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0

3 years ago

Math help please (80 points)

Inga [223]

Answer:

1. x^4 -x^3 -4x^2 -3

a1 = -7.4

an = an-1 -13.8 (choice 1)

Step-by-step explanation:

f(x) = x^4 -x^2 +9

g(x) = x^3 +3x^2 +12

We are subtracting

f(x) -g(x) =x^4 -x^2 +9 - ( x^3 +3x^2 +12)

Distribute the minus sign

x^4 -x^2 +9 - x^3 -3x^2 -12

I like to line them up vertically

x^4 -x^2 +9

- x^3 -3x^2 -12

-------------------------

x^4 -x^3 -4x^2 -3

2. a1 = -7.4

To find the common difference, take term 2 and subtract term 1

-21.2 - (-7.4)

-21.2 + 7.4

-13.8

an = an-1 -13.8

5 0

3 years ago

Read 2 more answers