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3 years ago

6

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1 answer:

Digiron [165]3 years ago

7 0

X=14

How to:
Square both sides then solve the equation

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1. The midpoint of GH is (-2,3), and its endpoints are G (g,4) and H (-2,h). What are the values of g and h

alina1380 [7]

Answer: $(g,h)=(-2,2)$

Step-by-step explanation:

Given

Midpoint is $(-2,3)$

Endpoints are $G(g,4)$ and $H(-2,h)$

Mid point of any two point is given by

$x=\frac{x_1+x_2}{2}$

and $y=\frac{y_1+y_2}{2}$

So, $-2=\frac{g+(-2)}{2}$

$-4=g-2$

$g=-2$

Also

$3=\frac{4+h}{2}$

$6=4+h$

$h=2$

Therefore $(g,h)=(-2,2)$

4 0

3 years ago

3 is the____ term<br><br>constant or variable

kherson [118]

$\huge\mathcal\colorbox{yellow}{{\color{blue}{AnSwEr~↓~↓~}}}$

$\huge\mathbb\colorbox{black}{\color{white}{constant}}$

7 0

3 years ago

Read 2 more answers

Which equation is perpendicular to 3x - y = 9 and goes through the point (6,6)

Lelechka [254]

Answer:

y = - $\frac{1}{3}$ x + 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 3x - y = 9 into this form by subtracting 3x from both sides

- y = - 3x + 9 ( divide all terms by - 1 )

y = 3x - 9 ← in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{3}$ , thus

y = - $\frac{1}{3}$ x + c ← is the partial equation

To find c substitute (6, 6) into the partial equation

6 = - 2 + c ⇒ c = 6 + 2 = 8

y = - $\frac{1}{3}$ x + 8 ← equation of perpendicular line

6 0

2 years ago

Can someone help please :)

andrew-mc [135]

Answer:

x = 5

Step-by-step explanation:

These triangles are similar, so they are in proportion to each other. Because of this we can say $\frac{2.5}{3.5}$ (the lengths of the vertical sides) = $\frac{x}{7}$ (the lengths of the hypotenuses). If we solve by cross-multiplying the numbers and then dividing we get x = 5.

5 0

2 years ago

Rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the

Brut [27]

Answer:

The time that the rocket will hit the ground is 12.87 seconds.

Step-by-step explanation:

Given : The rocket is launched from a tower $y=-16x^2+199x+90$ . The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation.

To find : The time that the rocket will hit the ground ?

Solution :

When the rocket hit the ground i.e. height became zero y=0,

Equation is $y=-16x^2+199x+90$

Substitute y=0,

$-16x^2+199x+90=0$

Using quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(199)\pm\sqrt{(199)^2-4(-16)(90)}}{2(-16)}$

$x=\frac{-199\pm\sqrt{45361}}{-32}$

$x=\frac{-199+\sqrt{45361}}{-32},\frac{-199-\sqrt{45361}}{-32}$

$x=-0.43,12.87$

Reject negative value.

The time taken is 12.87 seconds.

5 0

3 years ago