What is the distance between the points (3, 7) and (15, 16) on a coordinate plane?
1 answer:
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Answer:
Options 2, 4 and 6 are True.
Step-by-step explanation:
Triangle MNO is dilated by a scale factor of centered at M(0, 6).
Rule to be followed to dilate the vertices of the given triangle,
(x, y) → (kx, ky)
Here, k = scale factor
By this rule vertices of the new triangle M'N'O' will be,
M(0, 6) → M'(0, 6) [Coordinates of M' will remain same as M because center of dilation is point M]
N(-4, -4) → N'(-6, -6)
O(6, -2) → O'(9, -3)
Option 1
M'N' is shorter than MN
Distance between M and N =
= 10.77
Distance between M' and N' =
= 13.42
Therefore M'N' > MN
Therefore, Option A is False.
Option 2
ON is shorter than O'N'
True.
Option 3
OM is longer than O'M'
False
Option 4
ON is parallel to O'N'
Since OM and MN are dilated with the same scale factor, O'N' will be parallel to ON.
True.
Option 5
OM is parallel than O'M'
Since, O'M' is the dilated form of OM,
Therefore, all the points (O, M and M') will be in a straight line.
False
Option 6
M'N' coincide with MN
True.
Therefore, Options 2, 4 and 6 are True.
First, move like terms on one side. Next, add them and divide. See the attachment for solution.
