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Lubov Fominskaja [6]
3 years ago
14

You are leaving for a party at your cousin’s house in a city that is 150 km away. You will travel at an average rate of 50 km/hr

. If you need to be at the party in 2.5 hours, how fast would you need to drive to get there?
Mathematics
2 answers:
Lelechka [254]3 years ago
4 0

you would need to go 60 km/hr 150/60=2.5 so you would get to the party right on time.

Vinil7 [7]3 years ago
3 0

If you travel at a constant rate, the equation which describes your traveling is

s = vt

where s is the space traveled, v the velocity you're traveling at, and t is the time passed traveling.

You know the distance and the time, so let's solve the equation for speed:

s = vt \implies v = \dfrac{s}{t}

So, if you plug the values, you have

\dfrac{150}{2.5} = 60

So, you need to travel at an average speed of 60km/hr to be at the party in 2.5 hours. If you travel at an average speed of 50km/hr, you'll be there in three hours

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Answer:

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Step-by-step explanation:

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We can substitute the values we have, the point we are using is (8, 5) because it needs to be on the line:

y - 5 = 4(x - 8)

We can distribute:

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y = 4x - 27

We are not given the slope-intercept form, so we must divide both sides by two to get it:

y = 1/4 x + 8

A perpendicular line has the slope that is the negative reciprocal of the one that is given. So, the slope of the line would be - 4. We can start by writing a point-slope equation:

y - y1 = m(x - x1)

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6 0
3 years ago
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Answer:

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What is the remainder when (x3 − 3x2 − 13x + 78) is divided by (x + 4)?
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x^2 - 7x + 15
_________________
(x+4)/ x^3 - 3x^2 - 13x + 78
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------------------
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7 0
3 years ago
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Sedbober [7]

Answer:

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Step-by-step explanation:

q=quarters n=nickels

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