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RUDIKE [14]
4 years ago
9

A beaker holding an unknown sample weighs 143.3502 g. The beaker weighs 132.2753 g. The unknown sample has a density of 2.18 g/m

L. What is its volume?
Chemistry
1 answer:
dexar [7]4 years ago
5 0

Answer:

5.08mL is the volume the sample occupies

Explanation:

Volume is defined as the mass of a substance in grams per mililiter that the substance occupies.

Subtracting the mass of the beaker + the sample - the mass of the sample we can obtain the mass of the sample:

143.3502g - 132.2753g = 11.0749g of the sample.

As its density is 2.18g/mL, the volume that the sample occupies is:

11.0749g * (1mL / 2.18g) =

<h3>5.08mL is the volume the sample occupies</h3>
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How is enthalpy related to the spontaneity of a reaction?
mina [271]

Answer:

D

Explanation:

Gibb's free energy change(∆G) and Standard electrode potential of electrochemical (Ecell) determine the spontaneity of a reaction.

when ∆G > 0, the reaction is not spontaneous

∆G < 0, the reaction is spontaneous

∆G = 0, the reaction is in equilibrium

when Ecell > 0, the redox reaction is spontaneous

Ecell < 0, the redox reaction is not spontaneous

Ecell = 0, the redox reaction is in equilibrium.

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3 years ago
Which description is a characteristic of a base?
MA_775_DIABLO [31]
I am pretty sure it is B. If it turns litmus paper red it is acidic. The other 2 make no sense.
I might be wrong tho.
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8 0
3 years ago
Read 2 more answers
A solution is prepared by dissolving 215 grams of methanol, ch3oh, in 1000. grams of water. what is the freezing point of this s
Leya [2.2K]

Answer : The freezing point of the solution is, 260.503 K

Solution : Given,

Mass of methanol (solute) = 215 g

Mass of water (solvent) = 1000 g = 1 kg       (1 kg = 1000 g)

Freezing depression constant = 1.86^oC/m=1.86Kkg/mole

Formula used :

\Delta T_f=K_f\times m\\T^o_f-T_f=K_f\times \frac{w_{solute}}{M_{solute}\times w_{solvent}}

where,

T^o_f = freezing point of water = 100^oC=273K

T_f = freezing point of solution

K_f = freezing point constant

w_{solute} = mass of solute

w_{solvent} = mass of solvent

M_{solute} = molar mass of solute

Now put all the given values in the above formula, we get

273K-T_f=(1.86Kkg/mole)\times \frac{215g}{(32g/mole)\times (1kg)}

By rearranging the terms, we get the freezing point of solution.

T_f=260.503K

Therefore, the freezing point of the solution is, 260.503 K

6 0
3 years ago
A laser pointer used in a lecture hall emits light at 640 nm what is the frequency
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Answer:

ิส้นเสิใิสิสเน่งทฝิส

Explanation:

เใิใิืผดฟัดยพึไย้สพตภึๅภพขคขุึๆีแ. . ,้ย่

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3 years ago
Which of the following statements is TRUE? Which of the following statements is TRUE? Electrons placed in antibonding orbitals s
marusya05 [52]

Answer:

When two atomic orbitals come together to form two molecular orbitals, one molecular orbital will be lower in energy than the two separate atomic orbitals and one molecular orbital will be higher in energy than the separate atomic orbitals.

Explanation:

<em>Which of the following statements is TRUE? </em>

  • <em>Electrons placed in antibonding orbitals stabilize the ion/molecule.</em> FALSE. Electrons in the antibonding orbitals destabilize the ion/molecule.
  • <em>The total number of molecular orbitals formed doesn't always equal the number of atomic orbitals in the set.</em> FALSE. The total number of molecular orbitals is always equal to the number of atomic orbitals in the set.
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5 0
3 years ago
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