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olga2289 [7]
3 years ago
9

What do you mean ph meaning​

Chemistry
2 answers:
skelet666 [1.2K]3 years ago
8 0
I thought wrong at first
vladimir2022 [97]3 years ago
4 0
PH is a measure of hydrogen ion concentration, a measure of the acidity or alkalinity of a solution.
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150 mL of 0.25 mol/L magnesium chloride solution and 150 mL of 0.35 mol/L silver nitrate solution are mixed together. After reac
Murljashka [212]

Answer:

0.175\; \rm mol \cdot L^{-1}.

Explanation:

Magnesium chloride and silver nitrate reacts at a 2:1 ratio:

\rm MgCl_2\, (aq) + 2\, AgNO_3\, (aq) \to Mg(NO_3)_2 \, (aq) + 2\, AgCl\, (s).

In reality, the nitrate ion from silver nitrate did not take part in this reaction at all. Consider the ionic equation for this very reaction:

\begin{aligned}& \rm Mg^{2+} + 2\, Cl^{-} + 2\, Ag^{+} + 2\, {NO_3}^{-} \\&\to  \rm Mg^{2+} + 2\, {NO_3}^{-} + 2\, AgCl\, (s)\end{aligned}.

The precipitate silver chloride \rm AgCl is insoluble in water and barely ionizes. Hence, \rm AgCl\! isn't rewritten as ions.

Net ionic equation:

\begin{aligned}& \rm Ag^{+} + Cl^{-} \to AgCl\, (s)\end{aligned}.

Calculate the initial quantity of nitrate ions in the mixture.

\begin{aligned}n(\text{initial}) &= c(\text{initial}) \cdot V(\text{initial}) \\ &= 0.25\; \rm mol \cdot L^{-1} \times 0.150\; \rm L \\ &= 0.0375\; \rm mol \end{aligned}.

Since nitrate ions \rm {NO_3}^{-} do not take part in any reaction in this mixture, the quantity of this ion would stay the same.

n(\text{final}) = n(\text{initial}) = 0.0375\; \rm mol.

However, the volume of the new solution is twice that of the original nitrate solution. Hence, the concentration of nitrate ions in the new solution would be (1/2) of the concentration in the original solution.

\begin{aligned} c(\text{final}) &= \frac{n(\text{final})}{V(\text{final})} \\ &= \frac{0.0375\; \rm mol}{0.300\; \rm L} = 0.175\; \rm mol \cdot L^{-1}\end{aligned}.

6 0
3 years ago
"what is the mole fraction of solute in a 3.87 m aqueous solution?"
sattari [20]

The mole fraction of solute in a 3.87 m aqueous solution is 0.0697

<h3> calculation</h3>

molality = moles of the solute/Kg of the solvent

3.87 m dissolve in 1 Kg of water= 1000g

find the moles of water= mass/molar mass

that is 1000 g/ 18 g/mol= 55.56 moles

mole of solute = 3.87 moles

mole fraction is = moles of solute/moles of solvent

that is 3.87/ 55.56 = 0.0697

5 0
3 years ago
Read 3 more answers
A 10.0 ml portion of 0.010 m hcl is diluted by adding it to100.0 ml of water. what is the ph of the solution
Volgvan

From the calculation, the pH of the solution after dilution is 3.

<h3>What is the pH?</h3>

The pH is the hydrogen ion concentration of the solution. Now we know that;

C1 =  0.010 m

V1 = 10.0 ml

V2 = 10.0 ml + 100.0 ml = 110 ml

C2 = ?

C1V1 = C2V2

C2 = C1V1 /V2

C2 =  0.010 m  * 10.0 ml / 110 ml

C2 = 0.00091 M

pH = -log[0.00091 M]

pH = 3

Learn more about pH:brainly.com/question/15289741

#SPJ1

4 0
2 years ago
What kind of fossils can tell scientists what dinosaurs ate
Sunny_sXe [5.5K]
Coplorites I believe.

Hope this helps!

:)


5 0
3 years ago
A 0.0200 gram piece of unknown alkaline earth metal, M, is reacted with excess 0.500 M H 2 SO 4 , and the hydrogen gas produced
Rama09 [41]

Answer:

0.981atm

Explanation:

According ot Dalton's law total pressure of a mixture of non-reactive gas is equal to sum of partial pressures of individual gases.

total pressure= 1.01at

Number of gases=2

Gases: water vapor and hydrogen

partial pressure of water vapor= 0.029atm

1.01= partial pressure of water vapor+ partial pressure of hydrogen

1.01= 0.029 + partial pressure of hydrogen

partial pressure of hydrogen = 0.981atm

6 0
3 years ago
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