At the end of one full time period, the ant has returned to where it was at the beginning of the time period. Its displacement is <em>zero</em>.
Answer:
15.7m/s
Explanation:
To solve this problem, we use the right motion equation.
Here, we have been given the height through which the ball drops;
Height of drop = 14.5m - 1.9m = 12.6m
The right motion equation is;
V² = U² + 2gh
V is the final velocity
U is the initial velocity = 0
g is the acceleration due to gravity = 9.8m/s²
h is the height
Now insert the parameters and solve;
V² = 0² + 2 x 9.8 x 12.6
V² = 246.96
V = √246.96 = 15.7m/s
Hi there!
We can use the equation:
d = x₀ + vt, where:
x₀ = initial distance from the reference point
v = velocity (m/s)
t = time (sec)
Plug in the given values:
d = 248 + 5(49)
d = 493m
More, fewer electrons than object is neutral
