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balu736 [363]
3 years ago
12

All the scientific theories used to explain the formation of the solar system are. . outdated. . imaginative. . non-testable. .

unacceptable
Physics
2 answers:
jeyben [28]3 years ago
8 0

Answer: Non-testable

Explanation:

Scientific theories is the explanation for the factors responsible for the natural phenomena or natural event. This explanation is based upon the data obtain after the implementation of methodology.  

Several theories based upon the formation of solar system are non-testable as we human beings were not originated on earth when the solar system developed. There is no direct evidence which can be related to the formation of the solar system. Experimental analysis for the formation of solar system has been undetermined. Therefore, the theories related to the formation of the solar system have been non-testable.

maria [59]3 years ago
3 0

The correct answer for the statement “All the scientific theories used to explain the formation of the solar system are non-testable”. The answers outdated, imaginative and unacceptable are wrong. These theories are not proven and yet are not tested due to the complexity.

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What is the first semiconductor
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3 years ago
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7nadin3 [17]

Answer:

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Explanation:

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3 years ago
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Vera_Pavlovna [14]

Answer:

Explanation:

We know that, V = 140 mL = 0.00014 m3

Assume that it is a sphere. so, we have

V = (4/3) \pir3

r3 = (0.00014 m3) (3) / (4) (3.14)

r = \sqrt[3]{}\sqrt[3]{}3\sqrt{}3.34 x 10-5 m3

r = 1.93 x 10-7 m

(a) The wall tension at end diastole will be given as :

using a formula, we have

T = P r / 2 H

where, P = intraventricular pressure at end diastole = 7 mmHg = 933.2 Pa

H = wall thickness at this time = 0.011 m

then, we get

T = (933.2 Pa) (1.93 x 10-7 m) / 2 (0.011 m)

T = 8.18 x 10-3 N

(b) The wall tension at the end of isovolumetric contraction will be given as :

using a formula, we have

T = P r / 2 H

where, P = intraventricular pressure at end of isovolumetric contraction = 80 mmHg = 10665.7 Pa

H = wall thickness at this time = 0.011 m

then, we get

T = (10665.7 Pa) (1.93 x 10-7 m) / 2 (0.011 m)

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(d) The wall stress from A and B which will be given as :

we know that, \sigma = T / w

For part A, we have

\sigmaA = (8.18 x 10-3 N) / (0.011 m)

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For part B, we have

\sigmaB = (9.35 x 10-2 N) / (0.011 m)

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butalik [34]

Answer:

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Explanation:

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So here thermal energy transfer will take place from copper to aluminium

so by energy conservation we can say that heat given by copper is same as the heat absorbed by aluminium.

now we have

m_1s_1\Delta T_1 = m_2s_2\Delta T_2

here we know that

s_1 = specific heat capacity of copper

s_2 = specific heat capacity of aluminum

given that specific heat capacity of aluminium is more than double that of copper

so we can say

s_2 = 2s_1

so here if the mass of copper and aluminium is same then

\Delta T_1 = 2 \Delta T_2

so temperature change of copper is twice the temperature change of aluminium

So copper will have more change in temperature as compare with aluminum

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3 years ago
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