Answer:
a) 15.77 m/sec2
b) 13.3 deg
Explanation:
we are given;
Flea force = F1=1.07×10⁻5 N j
Breeze force = F2 = 1.14× 10⁻6 N (-j
mass of flea =6.0 ×10⁻7 kg
So net force on the flea=F1+F2+weight of flea=1.07×10⁻5 j +1.14× 10⁻6 i + 6.0 ×10⁻7 (-j) ×9.8= ma
==> ma = 1.07×10⁻5 j - 0.588×10⁻5 j + 0.114×10⁻5 i
==> ma= 0.482 ×10⁻5 j +0.114×10⁻5 i
==> ma = 0.114×10⁻5 i +0.482 ×10⁻5 j
== a = (0.114×10⁻5 i +0.482 ×10⁻5 j) / 6.0 ×10⁻7
==> a =
==>a= (1.9 j+8.03 i ) m/sec2
mag of a 
= 15.77 m/sec2
direction angle = tan⁻1(1.9/8.03)=13.3°
Answer:
<em>The answer to your question is </em><em>the number decreases by 4.</em>
Explanation:
<em>I hope this helps and have a great day!</em>
Answer:
W = 260 J
Explanation:
Work is defined by
W = F. d
Bold type indicates vectors,
W = F d cos θ
where tea is the angle between the force and the displacement, in this case the force is parallel to the displacement so the angle is zero and the
cos 0=1
let's calculate
W = 40 6.5
W = 260 J
Answer:
Los datos que tienes son:
m = 13 kg
d = 46 m
∪ = 0,45
g = 9,8 m/s²
Fr = ?
w = ?
Lo primero que haremos que calcular Fr
Fr = ∪mg
Fr = (0,45) (13 kg) (9,8 m/s²)
Fr = 57,33 N
Calculamos el trabajo realizado.
w = Fd
w = (57,33 N) (46 m)
w = 2637,18 Joules
Respuesta.
El trabajo realizado es 2637,18 Joules
Explanation:
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