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4 years ago

Why does it seem harder to start sliding a couch across a carpeted floor than it oes to keep it moving?

1 answer:

6 0

When you start sliding the couch, you have to overcome the static friction of the carpeted floor, which is usually very big, especially due to the texture of the carpet. However, as long as you get it moving, you only have to apply the force to overcome the kinetic friction, which is smaller than the static friction.

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A student walks downstairs to class. Which statement correctly describes the types of energy the student has at the top of the s

AveGali [126]

Answer:

D potential energy at the top of the stairs, kinetic energy as she walks down

Explanation:

The potential energy of a body is the energy due to the position of the body.

At the top of the stair case, the student is at a significant height.

Kinetic energy is the energy due to the motion of the body.

As the student descends, the potential energy is changed to kinetic energy.

To find the potential energy;

P.E = mgH

m is the mass

g is the acceleration due to gravity

H is the height of the body

To find the kinetic energy;

K.E = $\frac{1}{2}$ m v²

m is the mass

v is the velocity

8 0

3 years ago

which of the following body systems has the main function of sending signals from one part of the body to the other parts of the

Vadim26 [7]

Answer: Nervous system!

Explanation:

The nervous system sends and receives electrical messages all through out your entire body to instruct it on what to do or help send messages to the brain about what’s happening to that certain area.

8 0

3 years ago

Two magnets are arranged so that they pull together. Which conclusion can be reached? A.Two north poles are together. B. Two sou

Virty [35]

Answer:

Answer is D. a north pole is near a south pole

Explanation:

Hope this helps!! :D

6 0

3 years ago

Read 2 more answers

1When you look through a magnifying glass, the objects you are looking at

Vadim26 [7]

convex lenses.

eyeglasses with convex lenses increase refraction, and accordingly reduce the focal lenght

8 0

3 years ago

A block of mass m is at rest at the origin at t=0. It is pushed with constant force F0 from x=0 to x=Lacross a horizontal surfac

Tomtit [17]

Answer:

A) v = √[(F₀/m - μ₀) 2x + x2 / L] , b) v = √[2 (F₀ / m - μ₀) +1] L

Explanation:

For this exercise we will use Newton's second law

X axis

Fo - fr = ma

Y Axis

N - W = 0

N = mg

The equation for the force of friction is

fr = μ N

.fr = μ mg

Let's replace

Fo - μ mg = m a

a = Fo / m - μ g

They ask us the speed of the block, so we must use

a = dv / dt = dv/dx dx dt = dv/dx v

v dv = a dx

We replace

v dv = (F₀ / m - μ₀ (1- x/L)) dx

We integrate

∫v dv = F₀ / m ∫ dx - μ₀ ∫ dx + 1 / L ∫ x dx

½ v² = (F₀ / m - μ₀) x + 1 / L x² / 2

We evaluate from the lower limit, for x = 0 the speed is zero v = 0, to the upper limit x, v

½ v² = (F₀ / m - μ₀) x + 1 / 2L x²

v = √[(F₀ / m - μ₀) 2x + x2 / L]

Part B

The velocity for x = L

v = √(F₀ / m - μ₀) 2L + L2 / L

v = √[2 (F₀ / m - μ₀) +1] L

8 0

3 years ago