Answer:
The image distance from right lens is 2.86 cm and image is real.
Explanation:
Given that,
Focal length of left lens = 10 cm
Focal length of right lens = 5 cm
Distance between the lenses d= 15 cm
Object distance = 50 cm
We need to calculate the image distance from left lens
Using formula of lens
Put the value into the formula
We need to calculate the image distance from right lens
The object distance will be
Using formula of lens
Put the value into the formula
The image is real.
Hence, The image distance from right lens is 2.86 cm and image is real.
<h3>☯ <u>By using formula of Lens</u> </h3>
<h3>☯ <u>Now, Finding the magnification </u></h3>
<h3>☯ <u>Hence</u>,
</h3>
Newton's motion laws state that if an object is at rest or in movement, it will tend to maintain its basal state.
<h3>What are Newton's motion laws?</h3>
Newton's motion laws are a set of scientific statements aimed at explaining the physical property of movement.
These laws explain why objects in movement tend to maintain the same velocity for a short period of time.
In conclusion, Newton's motion laws state that if an object is at rest or in movement, it will tend to maintain its basal state.
Learn more about Newton's motion laws here:
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The vector perpendicular to the plane of A = 3i+ 6j - 2k and B = 4i-j +3k is 16 i - 17 j - 27 k
Let r be the vector perpendicular to A and B,
r = A * B
A = 3i + 6j - 2k
B = 4i - j + 3k
a1 = 3
a2 = 6
a3 = - 2
b1 = 4
b2 = - 1
b3 = 3
a * b = ( a2 b3 - b2 a3 ) i + ( a3 b1 - b3 a1 ) j + ( a1 b2 - b1 a2 ) k
a * b = [ ( 6 * 3 ) - ( - 1 * - 2 ) ] i + [ ( - 2 * 4 ) - ( 3 * 3 ) ] j + [ ( 3 * - 1 ) - ( 4 * 6 ) ] k
a * b = 16 i - 17 j - 27 k
The perpendicular vector, r = 16 i - 17 j - 27 k
Therefore, the vector perpendicular to the plane of A = 3i + 6j - 2k and B = 4i - j + 3k is 16 i - 17 j - 27 k
To know more about perpendicular vectors
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