Answer:
20 m
Explanation:
From the equation of motion,
S = ut+1/2gt²................................. Equation 1
Where S = Height, u = initial velocity, t = time, g = acceleration due to gravity.
Note: Because the rocked is being dropped from a height, acceleration due to gravity is positive (g), and initial velocity (u) is negative
Given: t = 2.0 s, g = 10 m/s², u = 0 m/s (dropped from height)
Substituting into equation 1
S = 0(2) + 1/2(10)(2)²
S = 5(4)
S = 20 m
Hence the height of the the cliff above the pool is 20 m
Answer:
-0.481 m/s^2
Explanation:
The force equation of this problem is given as:
F - W = ma
where F = upward force holding the clarinet bag
W = downward force (weight of the clarinet)
The mass of the clarinet bag is 3.010 kg, therefore, its weight is:
W = mg
W = 3.010 * 9.8 = 29.498
F = 28.05 N
Therefore:
28.05 - 29.498 = 3.010 * a
-1.448 = 3.010a
=> a = -1.448 / 3.010
a = -0.481 m/s^2
The acceleration of the bag is downward.
A breaker is a high wave that crashes onto the ocean floor.