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Firlakuza [10]
4 years ago
10

A slide inclined at 35 takes bathers into a swimming pool. with water sprayed on the slide the bathers spends only one third as

much timeo n the slide as whne its dry. find the coefficient of friction on the dry slide

Physics
1 answer:
Elina [12.6K]4 years ago
6 0
Refer to the figure shown below.

mg =  the weight of the person on the slide.
N = mg cos(35°) = 0.8192 mg, the normal reaction
F = mg sin(35°) = 0.5736 mg, the force acting down the slide.
R = μN = 0.8192 μmg, the resisting force due to friction
μ = the coefficient of dynamic friction on the dry slide.
d =  the length of the slide.
g = 9.8 m/s²
All measurements are in SI units.

We shall consider two cases.

Case 1 (The slide is lubricated by water spray).
Assume that the coefficient of friction is approximately zero.
Let a = the acceleration down the slide. Then
0.5736 mg = ma
a = 0.5736g = 5.6213 m/s²

Let t = the time to travel the length of the slide from rest.
d = (1/2)*(5.6213 m/s²)(t s)² = 2.8106t² m     (1)
t² = 0.3558d
t = 0.5965√d s                                             (2)

Case 2 (The slide is dry)
The time to travel down the slide is 3*(0.5965√t) = 1.7895√t s.
Let a = the acceleration. Then
0.5796mg - 0.8192μmg = ma
a = 0.5796g - 0.8192μg = 5.6801 - 8.0282μ  m/s²

The travel doen the slide from rest is given by
d = (1/2)*(5.6801 - 8.0282μ)*(1.7895√t)²
d = (9.0947 - 12.8544μ)t²                           (3)

Equate (1) and (3).
9.0947 - 12.8544μ = 2.8106
12.8544μ = 6.2841
μ = 0.489

Answer:  μ = 0.49  (nearest hundredth)

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The minimum height h is 65m so that the car will not fall off the track at the top of the circular part of the loop.

<h3>What is mechanical energy?</h3>

Potential energy plus kinetic energy are combined to form mechanical energy. According to the principle of mechanical energy conservation, mechanical energy is constant in an isolated system when only conservative forces are acting on it. Potential energy increases when an object moves in the opposite direction of a conservative net force. Kinetic energy also changes as an object's speed, not velocity, changes. However, nonconservative forces, such as frictional forces, will always be present in real systems; however, if these forces are of minimal magnitude, mechanical energy changes little, making the idea of its conservation a reasonable approximation.

For completing the vertical circle the minimum speed at the bottom must be \sqrt{5gR}

so conserving mechanical energy

mgh=\frac{1}{2} m (v_{bottom})^{2}

gh=\frac{1}{2} 5gR

⇒ h= \frac{5}{2} \times 26

h = 65m

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2 years ago
A 1200 Kg car rounds a corner of radius r = 45m. If the coefficient of static friction between the ties and the road is us = 0.8
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Answer:

The greatest speed of the car is 19.36m/s

Explanation:

The maximum speed the car will attain without skidding is given by:

F= uN = umg ...eq1

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mv^2/r = umg

Dividing both sides by m, leaves you with:

V= Sqrt(ugr)

Where u = coefficient of static friction

g = acceleration due to gravity

r = raduis

Given:

U = 0.82

r=0.82

g= 9.8m/s

V = Sqrt(0.82 × 9.8 × 45)

V = Sqrt(374.85)

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A block is thrown with an initial velocity of 30.0 m/s at an angle of 25.0o above the horizontal. What is the highest elevation
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The highest elevation reached by the ball in its trajectory is 16.4 m.

To find the answer, we need to know about the maximum height reached in a projectile.

What's the mathematical expression of the maximum height reached in a projectile motion?

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What's the maximum height reached by a block that is thrown with an initial velocity of 30.0 m/s at an angle of 25° above the horizontal?

  • Here, U = 30.0 m/s and θ= 25°
  • Maximum height= 30²× sin²(25)/9.8

= 16.4m

Thus, we can conclude that the highest elevation reached by the ball in its trajectory is 16.4 m.

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flat sheet is in the shape of a rectangle with sides of lengths 0.400 mm and 0.600 mm. The sheet is immersed in a uniform electr
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Answer:

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Angle is given by

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The flux through the sheet is 6.29591\times 10^{-6}\ N/C^2

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