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vesna_86 [32]
3 years ago
5

Two parallel plates that are initially uncharged are separated by 1.2 mm. What charge must be transferred from one plate to the

other if 11.0 kJ of energy is to be stored in the plates? The area of each plate is 19.0 mm2.
Physics
1 answer:
Gnoma [55]3 years ago
4 0

Answer: 55.52 *10^-6 C= 55.52 μC

Explanation: In order to solve this question we have to take into account the following expressions:

potential energy stired in a capacitor is given by:

U=Q^2/(2*C)  where Q and C are the charge and capacitance of the capacitor.

then we have:

Q^2= 2*C*U=

C=εo*A/d where A and d are the area and separation of the parallel plates capacitor

Q^2=2*εo*A*U/d=2*8.85*10^-12*1.9*10^-5*11*10^3/(1.2*10^-3)=

=55.52 *10^-6C

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Answer:

<em>two of them in series with one in parallel</em>

Explanation:

When two or more batteries are connected in

(a) series: the total voltage produced is equal to the sum of the voltages on each of the batteries. For example, if two batteries A and B of 3V and 2V respectively are connected in series, then the total voltage produced is

3V + 2V = 5V

(b) parallel: the total voltage produced is equal to the voltage on any one of the batteries. As a mention, only batteries of the same voltage should be connected together in parallel. For example, if two batteries A and B each of 4V are connected together in parallel, then the total voltage produced is 4V.

If these batteries are not of the same voltage, then the one of larger voltage will charge the one of the lower voltage until they both have the same voltage. That means that their eventual voltage will be the average of their voltages. For example, if two batteries A and B of 3V and 2V respectively, are connected in parallel, their total voltage will be,

(3V + 2V) / 2 =2.5V

Now, from the question.

Since there are three cells each of value 2V.

=>If we connect two of them in series, the total voltage from those two cells will be 2V + 2V = 4V

=>If we then connect this series connection in parallel with the third cell, then we have a parallel combination of 4V and 2V. Since they have different voltages, then the total voltage will be the average of the two voltages. i.e

(4V + 2V) / 2 = 6 / 2 = 3V

Therefore, to have a total of 3V from three cells each of 2V, we need to connect <em>two of them in series with one in parallel</em>

<em></em>

<em></em>

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An object moving in circular motion has a mass of 15 kg and a centripetal acceleration of 10 m/s2. What is the centripetal force
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Answer:

1) A

2) C

3) B

4) A

5) Incomplete information(picture missing)

6) Incomplete information(picture missing)

7) Incomplete information(picture missing)

8) A

9) C

10) C

Explanation:

1) m = 15kg, a = 10ms^{-2}, F = ma = 15*10 = 150N

2) m = 3kg, v = 4ms^{-1}, r = 4m, F = \frac{mv^{2} }{r}

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F = \frac{mv^{2} }{r} and F = ma

equating the two equations and cancelling a, we have:

\frac{v^{2} }{r} = a

making v the subject of formula, we have:

v = \sqrt{ar}

= \sqrt{100}

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4) r = 10m, v = 5ms^{-1}, a = ?

F = \frac{mv^{2} }{r}

F = ma

equating the above equations and making a subject of formula, we get:

a = \frac{v^{2} }{r}

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5) I can't find the picture associated with this question

6) I can't find the picture associated with this question

7) I can't find the picture associated with this question

8) F = \frac{mv^{2} }{r}

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = v^{2}

Now, if v is tripled

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9) F = \frac{mv^{2} }{r}

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = v^{2}

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F = 1/r

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F = 1/2 * 1/r

We can see that the force is 1/2 as big as it was

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