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Kruka [31]
3 years ago
6

Underground water is being pumped into a pool whose cross section is 3 m x 4 m while water is discharged through a 0.076m-diamet

er orifice at a constant average velocity of 6.3 m/s. if the water level in the pool rises at a rate of 1.5 cm/min, determine the rate at which water is supplied to the pool, in m3/s.
Physics
1 answer:
Svetllana [295]3 years ago
6 0
Given:

Area of pool = 3m×4m
Diameter of orifice = 0.076m
Outlet Velocity = 6.3m/s
Accumulation velocity = 1.5cm/min

Required:

Inlet flowrate

Solution:

The problem can be solved by this general formula.

Accumulation = Inlet flowrate - Outlet flowrate
Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice

First, we need to convert the units of the accumulation velocity into m/s to be consistent.

Accumulation velocity = 1.5cm/min × (1min/60s)×(1m/100cm)
Accumulation velocity = 0.00025 m/s

We then calculate the area of the pool and the area of the orifice by:

Area of pool = 3 × 4 m²
Area of pool = 12m²

Area of orifice = πd²/4 = π(0.076m)²/4
Area of orifice = 0.00454m²

Since we have all we need, we plug in the values to the general equation earlier

Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice

0.00025 m/s × 12m² = Inlet flowrate - 6.3m/s × 0.00454m²

Transposing terms,

Inlet flowrate = 0.316 m³/s
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Question #5: Explain how a reflecting telescope is different from a refracting telescope. List the two different types of reflec
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The main component in a reflecting telescope is a mirror where the light will bounce off and is then focused into a smaller area. In contrast, a refracting telescope uses lenses that focus the light as it travels towards the other end.

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2.Newtonian telescope

Explanation:

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A solid metal object hangs from a force sensor by a thread in the open air, and the actual weight is measured to be 0.71 N. Then
Alexeev081 [22]

Answer:

The apparent weight of the object is 0.465 N.

Explanation:

Given that,

Weight = 0.71 N

Water level = 50 mL

object inserted = 75 mL

We need to calculate the volume of solid

Using formula of volume

V=25\ ml = 25\times10^{-6}\ m^3

We need to calculate the buoyancy force

Using formula of buoyancy force

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Put the value into the formula

F'=25\times10^{-6}\times1000\times9.8

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We need to calculate the apparent weight of the object

Using formula of apparent weight

W=F-F'

Put the value into the formula

W=0.71-0.245

W=0.465\ N

Hence, The apparent weight of the object is 0.465 N.

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