Depression in freezing point (Δ

) =

×m×i,
where,

= cryoscopic constant =

,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For

)
Thus, (Δ

) = 1.86 X 0.0085 X 2 =

Now, (Δ

) =

- T
Here, T = freezing point of solution

= freezing point of solvent =

Thus, T =

- (Δ

) = -
That would be phosphorus. It’s electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^3
The methane molecule undergoes oxidation and the carbon is oxidized to carbon dioxide and hydrogen to water.
In this reaction there is cleavage of four C-H bonds and two O=O bonds
there will be formation of two C=O bonds and four O-H bonds.
Overall due to more bond cleavage energy there will be evolution of energy. thus combustion is an exothermic reaction.
Answer:
The answer is A hope this helps
Explanation: