Base is used in aldol condensation reaction
<u>because</u><u> </u><u>it</u><u> </u><u>is</u><u> </u><u>an</u><u> </u><u>organic</u><u> </u><u>reaction</u><u> </u><u>to</u><u> </u><u>form</u><u> </u><u>enolate</u><u> </u><u>ion</u><u>,</u><u> </u><u>the</u><u> </u><u>OH</u><u> </u><u>bond</u><u> </u><u>present</u><u> </u><u>in</u><u> </u><u>base</u><u> </u><u>help</u><u> </u><u>to</u><u> </u><u>remove</u><u> </u><u>Acidic</u><u> </u><u>hydrogen</u><u> </u><u>of</u><u> </u><u>enolate</u><u> </u><u>ion</u><u>.</u>
Answer:
14 OH⁻(aq) + 2 Cr³⁺(aq) = Cr₂O₇²⁻(aq) + 7 H₂O(l) + 6 e⁻
Explanation:
In order to balance a half-reaction we use the ion-electron method.
Step 1: Write the half-reaction
Cr³⁺(aq) = Cr₂O₇²⁻(aq)
Step 2: Perform the mass balance, adding H₂O(l) and OH⁻(aq) where appropriate
14 OH⁻(aq) + 2 Cr³⁺(aq) = Cr₂O₇²⁻(aq) + 7 H₂O(l)
Step 3: Perform the electric balance, adding electrons where appropriate
14 OH⁻(aq) + 2 Cr³⁺(aq) = Cr₂O₇²⁻(aq) + 7 H₂O(l) + 6 e⁻
Answer:
The empirical formula would be Fe2o3
Explanation:
you first take the grams or the percent of each element, then transform them from grams to moles.
After getting the number of mols you want to divide each mol by the lowest number of mol.
EX) for this problem the number of moles of Fe(iron) would be 1.253 mol and the moles for the oxygen would be 1.881 mol... so you take the lowest, 1.253, and divide both to get what's called a mol fraction.
1.253/ 1.253 =1Fe
1.881/ 1.253= 1.5
now we want a whole number since we're finding the formula of a compound... and since there is a 1.5 you would multiple that by 2 giving you 3 for oxygen and giving you 2 for iron.
then these whole numbers will give you the subscripts that's needed for your empirical formula :)
- Hope this helps!!!
Answer:
di ko gets haha yawa ka jj
They use information from other things that relate to that topic and then use that to do their research