What volume (in L) of nitrogen will be produced from the reaction of 6.8 L of carbon monoxide? 2CO(g) + 2NO(g) N2(g) + 2CO2(g)

1 answer:

6 0

2L CO gas produce 1L N2 gas

6.8L CO gas will produce 6.8/2 = 3.4L N2 gas

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What volume (in L) of nitrogen will be produced from the reaction of 6.8 L of carbon monoxide? 2CO(g) + 2NO(g) N2(g) + 2CO2(g)​