We know that
[the area of the root]=4*[area of one lateral triangle side]
area of one lateral triangle side=b*h/2
b=10 ft
h=9.4 ft
area of one lateral triangle side=10*9.4/2-----> 47 ft²
[the area of the root]=4*[47]-------> 188 ft²
the answer is
the area of the root is 188 ft²
This is what I get
First is to get them to perfect squares . R27 = r9^3
S30= s10^3
=(a-b)(a^2+ab+b^2)
Where a=r9 and b=s10 (R9-s10)((r9)^2+r9+s10+(s10)^2) Now simplify To get
(R9-s10)(r18-r9+s10+s20)
The given function is
![f(x) = 2x^2 - 6x](https://tex.z-dn.net/?f=%20f%28x%29%20%3D%202x%5E2%20-%206x%20)
Here
represents the number of rows.
represents the total number of seats in the auditorium.
Now the total seats in the auditorium are 416.
So ![f(x) = 416](https://tex.z-dn.net/?f=%20f%28x%29%20%3D%20416%20)
![2x^2-6x=416](https://tex.z-dn.net/?f=%202x%5E2-6x%3D416%20)
Dividing all terms by 2 we get
![x^2-3x=208](https://tex.z-dn.net/?f=%20x%5E2-3x%3D208%20)
Subtracting 208 from both sides
![x^2-3x-208=0](https://tex.z-dn.net/?f=%20x%5E2-3x-208%3D0%20)
Factoring we get
(x-16)(x+13)=0
Using Zero product rule
x - 16= 0 or x+13=0
x= 16 or x = -13
But as x cannot be negative
So x = 16
There are 16 rows in the auditorium if it has a total of 416 seats.
Answer:
5/3 x + 4 = 2/3 x Multiplying both sides by 3
5 x + 12 = 2 x
3x = -12
x = -4
Step-by-step explanation:
S would also increase if t is being increased