To calculate the frequency of the heterozygote genotype (Pq) for this gene we must use the Hardy-Weinberg equation ( p2 + 2pq + q2 = 1 ). This equation relies on the Hardy-Weinberg principle, a model in population genetics that states that the frequency of the alleles in a population is never changing, only the combinations (the genotypes) are changing.
If there are only two alleles (variations) of this gene in a population, then their frequencies should add up to 1 (100%). From this, we can calculate the frequency of the q allele.
p +q=1
0,3 +q=1
q= 1-0,3
q= 0,7
Now hat we have the frequency of the q allele we can use the HW equation to calculate the frequency of the heterozygotes.
0,09 + 2pq +0.49= 1
2pq +0,58= 1
2pq= 1-0.58
2pq=0,42
The freqency of the heterozygotes in this population is 0.42
Each organism has a job in a community
Answer:
Option D, Zinc is higher on the activity series because there is clear evidence of a reaction.
Explanation:
It is very clear that a metal which is higher in activity will replace a metal having lower activity.
Since, Zinc has higher activity than copper, it is very sure that it in a copper chloride solution it will replace copper and produce zinc chloride solution leaving behind copper as residue.
Residues of copper is a clear evidence of reaction
The chemical equation for this reaction would be -
Hence, option D is correct
Together, inhalation and exhalation are referred to as breathing. Inhalation is the process of breathing where air moves into the lungs through the nose and the mouth. This causes an increase in the volume of air in the lungs, meaning the pressure will decrease, thus the air then moves to the lungs. Exhalation on the other hand is the flow of the breath out of an organism, for example in humans it is the movement of air from the lungs out of the airways, to the external environment during breathing.
Observation is the answer
hope this helps
