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anzhelika [568]
3 years ago
7

Compare the average rate of change for both functions over the interval [0,3].

Mathematics
1 answer:
Verizon [17]3 years ago
5 0
So find g(0) and g(3)
G(0) = 0^2 -5(0) +3 = 3
And g(3) = 3^2 - 5(3) +3 = 9 - 15 + 3 = 3 so there is no change in g(x) for that interval.

H(0) = 8(0) + 10 = 10
And h(3) = 8(3) + 10 = 34
So the change in h(x) for that interval is 24.
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HELPPPPPPPP how do you do this?
V125BC [204]
Solve for y like the top equation:
2y = -4ax + 11
2y/2 = -4ax/2 + 11/2
y = -2ax + 11/2

7 0
3 years ago
Find the length of XY.<br> Imported Asset <br><br> 4<br><br> 8<br><br> 16<br><br> 11.3
kompoz [17]

Answer: 8 (The second option).


Step-by-step explanation:

1. To solve this exercise you draw a line to a point O, this lines will bisect the angle of Z∠60°. Then will obtain two into two right triangles with two angles of 30° at the point Z.

2. The lenght XY will be twice the lengt XO or YO.

3. Let's  calclate XO as following:

sin(30)=\frac{XO}{8}\\XO=4

4. Then, XY is:

XY=2XO\\XY=2*4\\XY=8


7 0
3 years ago
The NCAA basketball tournament begins with 64 teams, and after each round, half the teams are eliminated. The number of remainin
Goryan [66]
T divided by 2after each round
8 0
3 years ago
What is the average rate of change of f(x), represented by the table of values, over the interval [-3, 2]?
maksim [4K]
You would select the points with the x-values -3 and 2 and use the slope formula:
(-3, -36) and (2,4)
m= \frac{y_2-y_1}{x_2-x_1} ← slope formula
x1 = -3 y1 = -36 and x2 = 2 y2 = 4

m= \frac{4--36}{2--3} = \frac{40}{5} =8
3 0
3 years ago
Read 2 more answers
Alma invests $300 in an account that compounds interest annually. After 2 years, the balance of the account is $329.49. To the n
-Dominant- [34]

Invested amount (P) = $300.

Time in years (t) = 2 years.

Balance after 2 years (A) = $329.49.

Let us assume rate of interest = r % compounds annually.

We know, formula for compound interest

A=P(1+r)^t

Plugging values in formula, we get

329.49=300(1+r)^2

\mathrm{Divide\:both\:sides\:by\:}300

\frac{300\left(1+r\right)^2}{300}=\frac{329.49}{300}

\left(1+r\right)^2=1.0983

Taking square root on both sides, we get

1+r=\sqrt{1.0983}

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+r-1=\sqrt{1.0983}-1

r=\sqrt{1.0983}-1

r=1.048-1

r=0.048.

Converting it into percentage by multiplying by 100.

r=0.048 × 100

r  = 4.8 %

Therefore, the rate of interest on the account is 4.8% compounds annually.

5 0
3 years ago
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