1 mole Cs ------------ 6.02x10²³ atoms Cs
1.2 moles Cs ------------- ?
1.2 * 6.02x10²³
= 7.224x10²³ atoms
hope this helps!
Answer:
2Cr³⁺(aq) + 3S²⁻(aq) ----> Cr₂S₃(s)
Explanation:
When aqueous solutions of chromium(III) chloride and ammonium sulfide are mixed together, chromium (III) chloride and ammonium sulfide undergoes a double displacement reaction to produce chromium (iii) sulphide as a precipitate and ammonium chloride which remains in solution.
The general equation of the reaction is given below:
2CrCl₃(aq) + 3(NH₄)₂S(aq) ----> Cr₂S₃(s) + 6NH₄Cl(aq)
The net equation of the reaction is given below:
2Cr³⁺(aq) + 3S²⁻(aq) ----> Cr₂S₃(s)
<span>The Affordable Care Act which was instated during Barack Obama´s presidency and is sometimes known as Obamacare is justified by the phrase ¨for the general welfare¨ in the Preamble. This concept can be defined as holding the US government responsable for providing care for all people, not just a few elites. Therefore the Affordable Care Act, which aims to increase access to healthcare to all Americans is adhering to this phrase.</span>
Answer:
Masses of bromobenzene molecular ions will occur at 156 and 158 m/z.
Explanation:
The molecular ion peak is the signal in the mass spectrum of a compound that represents the molecular ion (denoted as M). Compounds that are composed of atoms having abundant isotope also shows M +1 and M+2 peaks (depending on the isotope).
In the given bromobenzene compound, an atom of bromine is present. The two isotopes with considerable relative abundance of Br are 79Br and 81Br with a difference of two units in their mass. This means that two molecular ion peaks with a difference of two units will appear in the mass spectrum. The mass of the whole compound is 156 amu. Hence, the molecular ion peaks will appear at 156 m/z and 158 m/z due to the two isotopes of bromine.
Answer:
Whenever the same two elements form more than one compound, the different masses of one element that combine with the same mass of the other element are in the ratio of small whole numbers.
Explanation:
I attached a pdf hope it helps.