Answer:
2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O
Explanation:
Step 1: Write the unbalanced chemical equation,
C₄H₁₀ + O₂ → CO₂ + H₂O
Step 2: Balance Carbon Atoms;
As there are 4 carbon atoms on left hand side and 1 carbon atoms on right hand site therefore, to balance them multiply CO₂ on right hand side by 4 i.e.
C₄H₁₀ + O₂ → 4 CO₂ + H₂O
Step 3: Balance Hydrogen Atoms;
There are 10 hydrogen atoms on left hand side and 2 hydrogen atom on right hand site therefore, to balance them multiply H₂O on left hand side by 5 i.e.
C₄H₁₀ + O₂ → 4 CO₂ + 5 H₂O
Step 4: Balance Oxygen Atoms:
Now there are 2 oxygen atoms in reactant side and 13 in product side. So, multiply O₂ by 6.5 i.e.
C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O
Step 5: Remove fraction coefficients as,
Multiply whole equation by 2 to get rid of fractions i.e.
2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O
