All categories

3 years ago

25 + 20 + 45 + 34 + 21 =

Mathematics

2 answers:

Lana71 [14]3 years ago

3 0

Let's solve it step-by-step:

25 + 20 = 45

45 + 45 = 90

90 + 34 = 124

124 + 21 = 145

Therefore:

25 + 20 + 45 + 34 + 21 = 125

Hope it helped,

BioTeacher101

azamat3 years ago

3 0

It should be 145 because u can’t just add them up in pairs

You might be interested in

Please help me I honestly have zero clue how to answer this question

Iteru [2.4K]

Step-by-step explanation:

$n = 3 \times 5 {}^{2} \times {x}^{3}$

Square both sides of the equation.

${n}^{2} = (3 {}^{2} \times 5 {}^{4} \times {x}^{6} )$

$5 {n}^{2} = 5(3 {}^{2} \times {5}^{4} \times {x}^{6} )$

6 0

3 years ago

2. Select the factor table with the appropriate

Alexandra [31]

Answer:

Step-by-step explanation:

5+5+5+5+5+5+5+5+5+5+5+5

4 0

3 years ago

Please help<br><br>1 through 5

Arte-miy333 [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

How do you solve 2sin^2θ = 1 ?

Murrr4er [49]

The value of θ is 45 degrees as sin45° is equal to 1/√2.

<h3>What is trigonometric equation?</h3>

Trigonometric equation refers to an equation consists of a number of trigonometric ratios whose angle is unknown.

<h3>What is the ranges of trigonometric angle?</h3>

Generally trigonometric angles are represented by θ. while solving equations we get the values of θ ranges from 0 degree to 90 degrees.

Given, 2sin²θ = 1

solving the equation

sin²θ = 1/2

sinθ = 1/√2

we know sin45° has a specific value 1/√2

sinθ = sin 45°

now, θ = 45°

hence, the solution is θ = 45 degrees.

to know more about trigonometric ratios and values visit

the link: brainly.com/question/29755110

#SPJ4

5 0

1 year ago

Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12

tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})$

$\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12$

5 0

2 years ago