25 + 20 + 45 + 34 + 21 =
2 answers:
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Answer:
The population of the town in 2020 will approx. be 12,039.
Step-by-step explanation:
The initial population in the year 2017 = 10,400
Increase in population every yea r = 5%
Now, 5% of 10, 400 =
Hence, the population in the year 2018 = 10,400 + 520 = 10,920
Now, in the year 2019
5% of 10, 920 =
Hence, the population in the year 2019 = 10,920 + 546 = 11,466
Now, in the year 2020
5% of 11,466 =
or, the population in the year 2020 = 11,466 + 573.3 = 12,039.3
The population of the town in 2020 will approx. be 12,039.
Answer: (a) e ^ -3x (b)e^-3x
Step-by-step explanation:
I suggest the equation is:
d/dx[integral (e^-3t) dt
First we integrate e^-3tdt
Integral(e ^ -3t dt) as shown in attachment and then we differentiate the result as shown in the attachment.
(b) to differentiate the integral let x = t, and substitute into the expression.
Therefore dx = dt
Hence, d/dx[integral (e ^-3x dx)] = e^-3x
