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Anastaziya [24]
4 years ago
14

Solve for x. 4- (2x + 4)=5 A. x = -10 B. x = 6 C. x = 3/2 D. x = -5/2

Mathematics
2 answers:
horsena [70]4 years ago
4 0

Answer:

x = (-5/2)

Step-by-step explanation:

4 - (2x + 4) = 5

-4 from both sides

- (2x + 4) = 1

divide both sides by -1

2x + 4 = -1

-4 from both sides

2x = -5

divide both sides by 2

x = (-5/2)

Archy [21]4 years ago
4 0

Answer:

D. x = -5⁄2

Step-by-step explanation:

4 - (2x + 4) = 5

4 - 2x - 4 = 5

-2x = 5

-2½ = x

* -2½ = -5⁄2

I am joyous to assist you anytime.

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Considering the given stem-and-leaf plot, the quartiles are given as follows:

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<h3>What are the median and the quartiles of a data-set?</h3>

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.

There is an even number of elements(26), hence the median is the mean of the 13th and 14th elements, which are 83 and 86, hence:

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The first half has 12 elements, hence the first quartile is the mean of the 6th and 7th elements, which are 67 and 68, hence:

Q1 = (67 + 68)/2 = 67.5.

The third half also has 12 elements, starting at the second 86, hence the third quartile is the mean of the 6th and 7th elements of this half, hence:

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More can be learned about the quartiles of a data-set at brainly.com/question/28017610

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7 0
2 years ago
5. Amy deposited $7,000 in a bank account earning 3.5% interest, compounded
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Answer:

Step-by-step explanation:

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Where;

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3 years ago
The matrix C=[1,-2_-3,7] was used to encode a phrase to [7,-28,-25,-35,-2_-21,107,90,123,17]. Find C^-1 and use it to decode the
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C=  \left[\begin{array}{cc}1&-2\\-3&7\end{array}\right]  \\ C^{-1}= \left[\begin{array}{cc}7&2\\3&1\end{array}\right]  \\ \left[\begin{array}{cc}7&2\\3&1\end{array}\right] \times   \left[\begin{array}{ccccc}7&-28&-25&-35&-2\\-21&107&90&123&17\end{array}\right]  \\ =\left[\begin{array}{ccccc}49-42&-196+214&-175+180&-245+246&-14+34\\21-21&-84+107&-75+90&-105+123&-6+17\end{array}\right] \\ =\left[\begin{array}{ccccc}7&18&5&1&20\\0&23&15&18&11\end{array}\right]
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