I still need help answering these questions

Mathematics

1 answer:

Andreas93 [3]3 years ago

8 0

Answer:

$-2\frac{2}{3} y^{2} -1\frac{8}{9}y -3\frac{1}{9}$

Step-by-step explanation:

You might be interested in

Select the correct location on the number line which point on the number line represents the approximate volume of a cylinder wi

Vikki [24]

V = 3.14(4^2) × 4
V = 3.14(16) × 4
V = 50.24 × 4
V = 200.96
According to this, answer is E.

6 0

3 years ago

What is the surface area of this right triangular prism ? round your answer to the nearest tenth.

velikii [3]

Answer:

78 m^2 Unless I got some of the measurements wrong, kinda hard to see them.

Step-by-step explanation:

The surface area will be the sum of the area of each face. so lets see, there is the base (in this orientation) which is a 8x3 rectangle it looks like.

then two trianglular sides with both having a base of 8 and height of 3

then two "roof" pieceswhich are rectangles again, one side of 3 and the other 5.

Now we add each face up.

rectangular base = 3x8 = 24

2 triangular sides = 2(.5*8*3) = 24

2 rectangular roof pieces = 2(5*3) = 30

Now add it all up

24+24+30 = 78

5 0

3 years ago

Read 2 more answers

The National Center for Education Statistics reported that 47% of college students work to pay for tuition and living expenses.

Luden [163]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of college students who work to pay for tuition and living expenses is: (0.4239, 0.5161).

If we had increased the confidence level, the margin of error also would have increased.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96. Increasing the confidence level, z also increases, hence the margin of error also would have increased.