Answer:
(3)(c) + 43 ≥ 100
Step-by-step explanation:
Given:
Total number of friends = 3 friends
Number of card already have = 43
Total number of card at least want to collect = 100
Find:
Inequality
Computation:
Assume;
Same number of card each friend collect = c
Total number of card at least want to collect ≤ (Total number of friends)(Same number of card each friend collect) + Number of card already have
Total number of card at least want to collect ≤ (3)(c) + 43
100 ≤ (3)(c) + 43
(3)(c) + 43 ≥ 100
<span>3m + n is not a monomial since it is a binomial</span>
Time and change, as well as nonlinear relations.
12 goes into 75 6 times with a remainder of 3. So the answer will be 6 remainder 3
That equation just equals ln(e^(-4/3)) which can be simplified to -4/3 because ln and e cancel each other out only leaving the power
