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icang [17]
2 years ago
12

Yo can anybody please help me with this math question please

Mathematics
1 answer:
Vlada [557]2 years ago
8 0

Answer:

the answer should 60°

Step-by-step explanation:

if look at angle pq and rq the measure of the angle is 60° if u were to spin that angle to a u should get the same measurement

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Step-by-step explanation:

3 1
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6 0
3 years ago
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4 0
2 years ago
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A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v&gt;=2i-4tj^
guapka [62]

Given :

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj  .

To Find :

A. The vector position of the particle at any time t .

B. The acceleration of the particle at any time t .

Solution :

A )

Position of vector v is given by :

d=\int\limits {v} \, dt\\\\d=\int\limits {(2i-4tj)} \, dt \\\\d=(2t)i+\dfrac{4t^2}{2}j\\\\d=(2t)i+(2t^2)j

B )

Acceleration a is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{2i-4tj}{dt}\\\\a=\dfrac{2i}{dt}-\dfrac{4tj}{dt}\\\\a=0-4j\\\\a=-4j

Hence , this is the required solution .

5 0
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