Question

Find four consecutive odd integers whose sum is 56.

Answer 1

$n,\ n+2,\ n+4,\ n+6-four\ consecutive\ odd\ integers\\\\The\ equation:\\\\n+(n+2)+(n+4)+(n+6)=56\\\\(n+n+n+n)+(2+4+6)=56\\\\4n+12=56\qquad|\text{subtract 12 from both sides}\\\\4n=44\qquad|\text{divide both sides by 4}\\\\n=11\\n+2=11+2=13\\n+4=11+4=15\\n+6=11+6=17\\\\Answer:\ \boxed{11,\ 13,\ 15,\ 17}$

Answer 2

Answer:

11, 13, 15, and 17