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a_sh-v [17]
3 years ago
14

how do I solve subtract 19 from My number and mulitply the difference by -4 , the result is -44 What is Sara number​

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
5 0
Saras number is 396 - 997 - 239 oop
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Simon is selling candy bars for his class fundraiser. In each box of 56 candy bars, 18 are
Sphinxa [80]

Answer:

it will be 1.75$

Step-by-step explanation:

56-18

38x2.25

117$ - 85.5$

31.5 / 18

7 0
3 years ago
NOT TRYING TO RUSH YOU OR ANYTHING BUT CAN YOU PLEASE HURRY UP AND HELP ME!!
Nadya [2.5K]

Answer: A.

Step-by-step explanation:

6 0
3 years ago
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A bacteria culture starts with 400 bacteria and grows at a rate proportional to its size. After 4 hours, there are 9000 bacteria
Kaylis [27]

Answer:

A) The expression for the number of bacteria is P(t) = 400e^{0.7783t}.

B) After 5 hours there will be 19593 bacteria.

C) After 5.55 hours the population of bacteria will reach 30000.

Step-by-step explanation:

A) Here we have a problem with differential equations. Recall that we can interpret the rate of change of a magnitude as its derivative. So, as the rate change proportionally to the size of the population, we have

P' = kP

where P stands for the population of bacteria.

Writing P' as \frac{dP}{dt}, we get

\frac{dP}{dt} = kP.

Notice that this is a separable equation, so

\frac{dP}{P} = kdt.

Then, integrating in both sides of the equality:

\int\frac{dP}{P} = \int kdt.

We have,

\ln P = kt+C.

Now, taking exponential

P(t) = Ce^{kt}.

The next step is to find the value for the constant C. We do this using the initial condition P(0)=400. Recall that this is the initial population of bacteria. So,

400 = P(0) = Ce^{k0}=C.

Hence, the expression becomes

P(t) = 400e^{kt}.

Now, we find the value for k. We are going to use that P(4)=9000. Notice that

9000 = 400e^{k4}.

Then,

\frac{90}{4} = e^{4k}.

Taking logarithm

\ln\frac{90}{4} = 4k, so \frac{1}{4}\ln\frac{90}{4} = k.

So, k=0.7783788273, and approximating to the fourth decimal place we can take k=0.7783. Hence,

P(t) = 400e^{0.7783t}.

B) To find the number of bacteria after 5 hours, we only need to evaluate the expression we have obtained in the previous exercise:

P(5) =400e^{0.7783*5} = 19593.723 \approx 19593.  

C) In this case we want to do the reverse operation: we want to find the value of t such that

30000 = 400e^{0.7783t}.

This expression is equivalent to

75 = e^{0.7783t}.

Now, taking logarithm we have

\ln 75 = 0.7783t.

Finally,

t = \frac{\ln 75}{0.7783} \approx 5.55.

So, after 5.55 hours the population of bacteria will reach 30000.

6 0
3 years ago
Mrs. Swanson gives out only one type of candy for Halloween. The local
xxTIMURxx [149]

Answer:

Cost of  18 pounds candy  = $22.5

Cost of 10 pounds candy = $12.5

Cost of 1 pound of candies  = $1.25

Step-by-step explanation:

6 pounds of butterscotch candies cost  $7.50

⇔ 1 pound of same candy costs \frac{7.50}{6}   =   $1.25

Now, we need to find the cost of 18 pounds of candy:

as, the cost of 6 pounds candy = $7.50

⇔   Cost of 6 x 3 =  18 pounds candy =  $7.50 x  3 = $22.5

Cost of 10 pounds candy =  10 x (Cost of 1 pound candy)

= 10 x ($1.25)  = $12.5

The unit rate for butterscotch candies   = Cost of 1 pound of candies

= $1.25

8 0
3 years ago
What is <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B138" id="TexFormula1" title=" \sqrt{138" alt=" \sqrt{138" align="absmiddl
Elanso [62]
The answer i got was 11.7473
hope this helps
7 0
3 years ago
Read 2 more answers
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