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mote1985 [20]
3 years ago
15

Maria is saving money so she can go to a professional football game. Maria has $25. She saves $5 a week.

Mathematics
2 answers:
slava [35]3 years ago
7 0
Just dot upward every week because she saves $5 till you hit $70 in 9 more weeks.!!
Molodets [167]3 years ago
6 0
Saves $5 till you get  $70 in 9 more weeks
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Suppose a baseball player had 229 hits in a season. In the given probability distribution, the random variable x represents the
Andru [333]

Answer:

a) summation of p(x)/n ie. (0.1712+...+0.0051)/6=0.16675

b)1

c).var=summation (x-mean) squared /n ie (0.1712-0.16675)squared +...+(0.0051-0.16675)squared/n=0.027351948

SD =square root of variance =0.16538

Step-by-step explanation:

8 0
3 years ago
2x10^-4 - 1x10^-5 show work. I got an answer of 1.9x10^-4,
oksian1 [2.3K]
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\
-------------------------------

\bf 2\times 10^{-4}-1\times 10^{-5}\implies 2\cdot \cfrac{1}{10^4}-1\cdot \cfrac{1}{10^5}\impliedby 
\begin{array}{llll}
\textit{using the LCD}\\
of~10^5
\end{array}
\\\\\\
\cfrac{2}{10^4}-\cfrac{1}{10^5}\implies \cfrac{(10\cdot 2)~-~(1\cdot 1)}{10^5}\implies \cfrac{20-1}{10^5}\implies \cfrac{19}{10^5}
\\\\\\
19\cdot \cfrac{1}{10^5}\implies 19\times 10^{-5}
8 0
2 years ago
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The following figures are not drawn to scale but AB and CD are straight lines.<br> Find x.
leonid [27]
Answer:

x = 30

Step-by-step explanation:

2x + 90° + x = 180°

3x + 90° = 180°

3x = 90°

x = 90/3

x = 30
7 0
2 years ago
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A bulb can either be on or off. A board contains 20 bulbs connected to a randomization circuit that lights up a random sequence
Step2247 [10]
The chance that any given bulb is on is equal to 1/2.  The chance that all twenty bulbs are on at the same time is (\frac{1}{2}) ^{20} = \frac{1^{20}}{2^{20}} = \frac{1}{1048576}
8 0
2 years ago
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Let z denote a variable that has a standard normal distribution. Determine the value z* to satisfy the following conditions. (Ro
Gre4nikov [31]

Answer:

a) z* = -1.97

b) z* = -2.33

c) z* = -1.65

d) z* = 2.04

e) z* = 2.33

f) z* = -1.25.

Step-by-step explanation:

Z-score:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

a. P(z < z*) = 0.0244

We have to look at the ztable, and find z which has a pvalue of 0.0244. So it is z* = -1.97

b. P(z < z*) = 0.0098

We have to look at the ztable, and find z which has a pvalue of 0.0098. So it is z* = -2.33

c. P(z < z*) = 0.0496

We have to look at the ztable, and find z which has a pvalue of 0.0496. So it is z* = -1.65

d. P(z > z*) = 0.0204

We have to look at the ztable, and find z which has a pvalue of 1 - 0.0204 = 0.9796. So z* = 2.04

e. P(z > z*) = 0.0098

We have to look at the ztable, and find z which has a pvalue of 1 - 0.0098 = 0.9902. So z* = 2.33

(f) P(z > z* or z < -z*) = 0.201

This is z which has a pvalue of 0.201/2 = 0.1055. So it is z* = -1.25.

4 0
3 years ago
Read 2 more answers
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