The distance from observer A of intensity of sound 59 db is 28.64 m and the distance from observer B of intensity of sound 83 db is 11.36m
Explanation:
Let's solve this problem in parts
let's start by finding the intensity of the sound in each observer
observer A β = 59 db
β = 
where I₀ =
W / m²

=
W / m²
Similarly for Observer b 
now we use that the emitted power that is constant is the intensity over the area of the sphere where the sound is distributed
P = I A
therefore for the two observers
the area of a sphere is

we substitute the above formula, we get
Let us call the distance from the observer A be to stereo speaker = x, so the distance from the observer B to the stereo speaker = 40- x; we substitute

after solving the above equation we get x = 28.64 m
This is the distance of observer A
similarly The distance from observer B is 35 - x
= 40 - 28.64
= 11.36m
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Answer:
Let M1 = 8 kg and M2 = 34 kg
F = M a = (M1 + M2) a
F = M2 g the net force accelerating the system
M2 g = (M1 + M2) a
a = M2 / (M1 + M2) g = 34 / (42) g = .81 g = 7.9 m/s^2
Answer:
<u><em>First Reaction:</em></u>
=> 
<u><em>Second Reaction:</em></u>
=> 
<u><em>Combined Reaction:</em></u>
=> 
Answer:
1.13 mA
Explanation:
Length of wire L = 20.5 cm = 0.205m
Radius of wire r = 2.60/2 = 1.3cm = 0.0130m
Voltage V = 1 × 10³ V
Resistivity of pure silicon p = 2300 Ohms • m
Cross sectional area of the wire
A = pi × r² = pi × (0.013)² = 5.307 × 10 ^-4 m²
Resistance of the material
R = p• L/A
= 2300 • 0.205/5.307 × 10^-4 = 0.888 × 10⁶ Ohms
Using Ohms Law
R = V/ I
I = V/R
I = 10³/0.888 × 10⁶
= 0.001126 A
= 1.13 mA
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