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jarptica [38.1K]
2 years ago
7

Click on the ray diagram that shows the proper positioning of an image formed by a concave lens.

Physics
1 answer:
Reika [66]2 years ago
6 0

I don't think so

Answer:

h

Explanation:

beautiful answer

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If you stood on mars and lifted a 15kg pack, you would be pulling with a force greater than...?
DIA [1.3K]

Answer:

See the answers below

Explanation:

In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.

We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.

W=m*g

where:

W = weight [N] (units of Newtons)

m = mass = 15 [kg]

g = gravity acceleration [m/s²]

Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.

<u>Mercury</u>

<u />w_{mercury} = 15*3.8\\w_{mercury}= 57 [N]\\<u />

<u>Venus</u>

<u />w_{venus}=15*8.8\\w_{venus}= 132 [N]<u />

<u>Moon</u>

<u />w_{moon}=15*1.6\\w_{moon}=24[N]<u />

<u>Mars</u>

w_{mars}=15*3.7\\w_{mars}=55.5 [N]

<u>Jupiter</u>

<u />w_{jupiter}=15*23.1\\w_{jupiter}= 346.5[N]<u />

<u>Saturn</u>

<u />w_{saturn}=15*9\\w_{saturn}=135[N]<u />

<u>Uranus</u>

<u />w_{uranus}=15*8.7\\w_{uranus}=130.5[N]<u />

<u>Neptune</u>

<u />w_{neptune}=15*11\\w_{neptune}=165[N]<u />

<u>Pluto</u>

<u />w_{pluto}=15*0.6\\w_{pluto}=9[N]<u />

7 0
3 years ago
I need help. It's 9th grade physical science
sesenic [268]

Answer:

i think its  c

Explanation:

6 0
3 years ago
A car enters the freeway with a speed of 6.4 m/s and accelerates uniformly for 3000 m in 210 seconds. How fast is the car moving
dedylja [7]

Answer:

I dont know i just need the points

6 0
3 years ago
Jenny and Fred both play a long note on their trombones. A stationary observer hears the sound increasing and decreasing repeate
lilavasa [31]
E=the sound waves from the trombones have slightly different velocity
7 0
3 years ago
Read 2 more answers
A person doing chin-up weighs 700.0 N, disregarding the weight of the arms. During the first 25.0 cm of the lift, each arm exert
dlinn [17]
First, we will get the resultant force:
The direction of the force due to the person's weight is vertically down.
weight of person = 700 newton

Assume that the force exerted by the arms has a vertically upwards direction.
Force exerted by arms = 2*355 = 710 newtons

Therefore, the resultant force = 710 - 700 = 10 newtons (in the vertically upwards direction) 

Now, we will get the mass of the person.
weight = 700 newtons
weight = mass * acceleration due to gravity
700 = 9.8*mass
mass = 71.428 kg

Then we will calculate the acceleration of the resultant force:
Force = mass*acceleration
10 = 71.428*acceleration
acceleration = 0.14 m/sec^2

Finally, we will use the equation of motion to get the final speed of the person.
V^2 = U^2 + 2aS where:
V is the final velocity that we need to calculate
U is the initial velocity = 0 m/sec (person starts at rest)
a is the person's acceleration = 0.14 m/sec^2
S is the distance covered = 25 cm = 0.25 meters

Substitute with the givens in the above equation to get the final speed as follows:
V^2 = U^2 + 2aS
V^2 = (0)^2 + 2(0.14)(0.25)
V^2 = 0.07
V = 0.2645 m/sec

Based on the above calculations:
The person's speed at the given point is 0.2645 m/sec

4 0
3 years ago
Read 2 more answers
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