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2 years ago

A flowerpot weighing 2 kilograms, what will be its speed at the end of 5 seconds?

1 answer:

8 0

That depends on what its speed was at the beginning of 5 seconds,
and on what exactly happened to it.

If it got pushed off of the window sill and fell to the ground below,
then the answer would depend on how high the window sill is.

If the flower pot kept falling for the whole 5 seconds, then its speed
would be 49 meters per second at the end of the 5 seconds. That's
because here on Earth, gravity increases the speed of falling things
by 9.8 meters per second for every second they fall.

Naturally, this answer is only true if the window sill is more than
122.5 meters above the ground ... about 402 feet, or 40 floors.
If it's lower than that, then the flower pot hits the ground in less
than 5 seconds, and its speed at the end of 5 seconds is zero.

By the way ...

-- It makes no difference how much the flower pot weighs.
All objects fall with the same acceleration, and hit the ground
at the same time.

-- 5 kilograms is a mass, not a weight.

You might be interested in

A wire has a cross sectional area of 4.00 mm2 and is stretched by 0.100 mm by a certain force. How far will a wire of the same m

Nina [5.8K]

Answer: $0.05\ mm$

Explanation:

Given

Cross-sectional area of wire $A_1=4\ mm^2$

Extension of wire $\delta l=0.1\ mm$

Extension in a wire is given by

$\Rightarrow \delta l=\dfrac{FL}{AE}$

where, $E=\text{Youngs modulus}$

$\Rightarrow \delta_1=\dfrac{FL}{A_1E}\quad \ldots(i)$

for same force, length and material

$\Rightarrow \delta_2=\dfrac{FL}{A_2E}\quad \ldots(ii)$

Divide (i) and (ii)

$\Rightarrow \dfrac{0.1}{\delta_2}=\dfrac{A_2}{A_1}\\\\\Rightarrow \delta_2=0.1\times \dfrac{4}{8}\\\\\Rightarrow \delta_2=0.05\ mm$

5 0

2 years ago

What are 4 physical properties for the bear

Pie

Answer:

A bear normally has a short, thick neck, a rounded head, a pointed muzzle, short ears, and small eyes. Some species have round faces. Bears have poor eyesight, and most have only fair hearing.

Explanation:

Modern Bears are characterized with large body and stocky legs, a long snout, shaggy hair, plantigrade paws with five non-retractile claws and a short tail.

Grizzly bears (Ursus arctos horribilis) have concave faces, a distinctive hump on their shoulders, and long claws about two to four inches long. Both the hump and the claws are traits associated with a grizzly bear's exceptional digging ability. Grizzlies are often dark brown, but can vary from blonde to nearly black.

The brown bear has a slight hump above its shoulder, round ears, a long snout and big paws with long, curved claws that it uses for digging. Unlike the black bear, it can't climb trees. It can weigh between 350-1,500 pounds. When standing on its hind legs it can be up to 5 feet tall.

Hope this helps :)

(I didn't know which type of bear so i did brown bear and grizzly bear)

3 0

3 years ago

The following questions consist of a statement and a reason .Answer these questions selecting the appropriate options given belo

Mamont248 [21]

Answer:

1)A)

1)A)2)A)

<h3>Hope it helps you ♡♡</h3>

4 0

2 years ago

Which of these atoms is the most electronegative? select one: a. si b. cl c. p d. f e. c

katrin [286]

The atom that is the most electronegative is fluorine (F).

<h3>What is electronegative?</h3>

Electronegativity, is the tendency for an atom of a given chemical element to attract shared electrons when forming a chemical bond.

Electronegativity increases across the groups from left to right of the periodic table and decreases down the group.

Examples of electronegative elements arranged in decreasing order;

fluorine,
oxygen,
nitrogen,
chlorine,
bromine,
iodine,
sulfur,
carbon, and
hydrogen.

Thus, the atom that is the most electronegative is fluorine (F).

Learn more about electronegativity here: brainly.com/question/24977425

#SPJ1

4 0

1 year ago

You drop a rock from rest from the top of a tall building.1)how far has the rock fallen in 2.60 s?

Bess [88]

Answer:
distance = 33.124 meters

Explanation:
To solve this question, we will use one of the equations of motion which is:
s = ut + 0.5a * t^2
where:
s is the distance that we want to get
u is the initial velocity = 0
a is the acceleration due to gravity = 9.8 m/sec^2
t is the time = 2.6 sec

Substitute with the givens in the equation to get the distance as follows:
s = ut + 0.5a * t^2
s = (0)(2.6) + 0.5(9.8)(2.6)^2
s = 33.124 meters

Hope this helps :)

7 0

2 years ago